英文:
How to transform Flow<List<Flow<List<T>>>> to Flow<List<List<T>>>?
问题
仅期望一个单一Flow包装在整个内容之外，而不是在内部有更多的Flow（内部Flow的内容更改应该只是简单地更改外部Flow的内容）。
英文:
Consider the following,
val tabs: MutableStateFlow<List<Path>> = getFlowPaths() // user defined//A function Path.contents(glob: String = "*"): Flow<List<Path>>val tabsFlow: Flow<List<Flow<List<Path>>>> = tabs.transformLatest {emit(it.map { path ->path.contents()})}//But I want tabsFlow to be Flow<List<List<Path>>>, is it possible to get it?
What I'm expecting,
Only a single Flow wrapped outside the whole thing rather than having more flow inside (change in content of inside flow should just simply change the content of outside flow).
答案1
得分: 0
以下是翻译好的代码部分：
一种可能的方法是：val tabsFlow: Flow<List<List<Path>>> = tabs.flatMapLatest { paths ->combine(paths.map { path ->path.contents()}) { it.toList() }}或val contentsFlows: List<Flow<List<Path>>> = tabs.value.map { path ->path.contents()}val res: Flow<List<List<Path>>> = combine(contentsFlows) { contents ->contents.toList()}
英文:
One possible way to do this:
val tabsFlow: Flow<List<List<Path>>> = tabs.flatMapLatest { paths ->combine(paths.map { path ->path.contents()}) { it.toList() }}
or
val contentsFlows: List<Flow<List<Path>>> = tabs.value.map { path ->path.contents()}val res: Flow<List<List<Path>>> = combine(contentsFlows) { contents ->contents.toList()}
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