英文:
C++ function not working properly with default char argument
问题
我有一段代码片段，其中声明了带有char和int类型默认参数的C++函数。
#include <iostream>
using namespace std;
int print(char c = '*', int num = 10);
int print(char c, int num)
{
for (int i = 0; i < num; i++)
{
cout << c << endl;
}
cout << endl;
return 0;
}
int main()
{
int rep;
char letter;
cout << "Enter a character: ";
cin >> letter;
cout << "Enter the number of times it has to repeat: ";
cin >> rep;
print(letter, rep);
print(rep);
print(letter);
return 0;
}
对于 print(rep); 没有输出，尽管给定了字符的默认参数。有任何想法为什么会发生这种情况吗？
我尝试使用默认参数，但char的默认参数不按预期工作，因此没有预期的字符输出。
英文:
I have a snippet of code where C++ functions are declared with default argument of char and int type.
#include <iostream>
using namespace std;
int print(char c = '*', int num = 10);
int print(char c, int num)
{
for (int i = 0; i < num; i++)
{
cout << c << endl ;
}
cout << endl;
return 0;
}
int main()
{
int rep;
char letter;
cout << "Enter a character : ";
cin >> letter;
cout << "Enter the number of times it has to repeat : ";
cin >> rep;
print(letter, rep);
print(rep);
print(letter);
return 0;
}
There is no output for print(rep);
even though default argument for character is given. Any idea why this is happening?
I tried to use default arguments, but default argument of char is not working as intended and there is no intended character output for that.
答案1
得分: 2
参数仍然按顺序排列。只能省略末尾的参数。当你调用print(rep)时，整数会转换为char，并默认为num。如果你输入，比如说，值为“65”（表示‘A’的代码），你会注意到这一点。
英文:
Arguments are still in order. You can only omit arguments from the end. When you call print(rep), the integer gets converted to a char and num gets defaulted. You'll notice if you enter, say, "65" (the code for 'A') as the value for rep.
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