在文本字符串中查找Python的值

huangapple
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英文:

Python find value in text string

问题

我正在使用Python编写一个网络自动化脚本，遇到了一个我不知道如何解决的问题。我有以下输出：

  1. CPE-MGT {
  2.     instance-type virtual-router;
  3.     interface ge-0/0/0.0;
  4.     routing-options {
  5.         static {
  6.             route 192.168.253.115/32 next-hop 192.168.100.1;
  7.             route 0.0.0.0/0 next-hop 192.168.100.1;
  8.         }
  9.     }
  10. }
  11. DATA {
  12.     instance-type virtual-router;
  13.     interface ge-0/0/1.0;
  14. }
  15. MGMT_BK {
  16.     instance-type virtual-router;
  17.     interface ge-0/0/2.0;
  18.     routing-options {
  19.         static {
  20.             route 192.168.253.115/32 next-hop 192.168.100.1;
  21.             route 0.0.0.0/0 next-hop 192.168.100.1;
  22.         }
  23.     }
  24. }

我需要获取特定主键接口的名称所在的位置；也许如果我举个例子会更清楚。

我有一个正则表达式，它查找文本并发现ge-0/0/0.0现在在文本中；我不知道的是如何获取CPE-MGT。

  1. cmd = net_connect.send_command(
  2.         juniper_cmds["sh_routing_instance"])
  3.     logger.debug(f'{ip_dict[config_dict["csv_ip_column"]][ips]}:设备路由实例 {cmd}')
  4.     regex_routing_instance = re.compile(f'{interface[0]}')
  5.     routing_instance = regex_routing_instance.findall(cmd)

希望这对你有帮助。

英文:

I am building a network automation script in python, and I got into a problem that I don't know how to resolve. I have the following output

  1. CPE-MGT {
  2.     instance-type virtual-router;
  3.     interface ge-0/0/0.0;
  4.     routing-options {
  5.         static {
  6.             route 192.168.253.115/32 next-hop 192.168.100.1;
  7.             route 0.0.0.0/0 next-hop 192.168.100.1;
  8.         }
  9.     }
  10. }
  11. DATA {
  12.     instance-type virtual-router;
  13.     interface ge-0/0/1.0;
  14. }
  15. MGMT_BK {
  16.     instance-type virtual-router;
  17.     interface ge-0/0/2.0;
  18.     routing-options {
  19.         static {
  20.             route 192.168.253.115/32 next-hop 192.168.100.1;
  21.             route 0.0.0.0/0 next-hop 192.168.100.1;
  22.         }
  23.     }
  24. }

I need to obtain the name of there I find the name of specific primary key interfaces; perhaps it will be clearer if I give an example.

I have a regex that looks into the text and finds that ge-0/0/0.0 is in the text now; what I don't know is how to obtain CPE-MGT.

  1. cmd = net_connect.send_command(
  2.         juniper_cmds["sh_routing_instance"])
  3.     logger.debug(f'{ip_dict[config_dict["csv_ip_colum"]][ips]}:Device routing instances {cmd}')
  4.     regex_routing_instance = re.compile(f'{interface[0]}')
  5.     routing_instance = regex_routing_instance.findall(cmd)```
  7. </details>
  10. # 答案1
  11. **得分**: 2
  13. 你可以使用两个模式和 `regex` 模块来实现递归：
  15. ```python
  16. import regex as re
  18. data = &quot;&quot;&quot;
  19. CPE-MGT {
  20.     instance-type virtual-router;
  21.     interface ge-0/0/0.0;
  22.     routing-options {
  23.         static {
  24.             route 192.168.253.115/32 next-hop 192.168.100.1;
  25.             route 0.0.0.0/0 next-hop 192.168.100.1;
  26.         }
  27.     }
  28. }
  29. DATA {
  30.     instance-type virtual-router;
  31.     interface ge-0/0/1.0;
  32. }
  33. MGMT_BK {
  34.     instance-type virtual-router;
  35.     interface ge-0/0/2.0;
  36.     routing-options {
  37.         static {
  38.             route 192.168.253.115/32 next-hop 192.168.100.1;
  39.             route 0.0.0.0/0 next-hop 192.168.100.1;
  40.         }
  41.     }
  42. }
  43. &quot;&quot;&quot;
  45. rx_block = re.compile(r&quot;&quot;&quot;
  46.     ^(?P&lt;name&gt;[A-Z_-]+)\s+
  47.     (?P&lt;body&gt;\{
  48.         (?:(?:[^{}]+)|(?2))+
  49.     \})
  50. &quot;&quot;&quot;, re.M | re.X)
  52. rx_inner = re.compile(r&quot;interface ge-0/0/0.0;&quot;)
  54. for block in rx_block.finditer(data):
  55.     m = rx_inner.search(block.group(&#39;body&#39;))
  56.     if m:
  57.         print(block.group(&#39;name&#39;))

这将产生以下结果：

  1. CPE-MGT

这里有两点需要注意：你实际上不需要使用正则表达式进行内部搜索，因为它是一个静态字符串，另外，可能应该使用解析器解决方案。你可以在 regex101.com 上查看该表达式的演示。

英文:

You could use two patterns and the regex module which offers recursion:

  1. import regex as re
  3. data = &quot;&quot;&quot;
  4. CPE-MGT {
  5.     instance-type virtual-router;
  6.     interface ge-0/0/0.0;
  7.     routing-options {
  8.         static {
  9.             route 192.168.253.115/32 next-hop 192.168.100.1;
  10.             route 0.0.0.0/0 next-hop 192.168.100.1;
  11.         }
  12.     }
  13. }
  14. DATA {
  15.     instance-type virtual-router;
  16.     interface ge-0/0/1.0;
  17. }
  18. MGMT_BK {
  19.     instance-type virtual-router;
  20.     interface ge-0/0/2.0;
  21.     routing-options {
  22.         static {
  23.             route 192.168.253.115/32 next-hop 192.168.100.1;
  24.             route 0.0.0.0/0 next-hop 192.168.100.1;
  25.         }
  26.     }
  27. }
  28. &quot;&quot;&quot;
  30. rx_block = re.compile(r&quot;&quot;&quot;
  31. 	^(?P&lt;name&gt;[A-Z_-]+)\s+
  32. 	(?P&lt;body&gt;\{
  33. 		(?:(?:[^{}]+)|(?2))+
  34. 	\})
  35. &quot;&quot;&quot;, re.M | re.X)
  37. rx_inner = re.compile(r&quot;interface ge-0/0/0.0;&quot;)
  39. for block in rx_block.finditer(data):
  40. 	m = rx_inner.search(block.group(&#39;body&#39;))
  41. 	if m:
  42. 		print(block.group(&#39;name&#39;))

<hr>

This would yield

  1. CPE-MGT

Two notes here: you wouldn't really need a regular expression for the inner search as it is a static string and two - probably use a parser solution instead.
See a demo for the expression on regex101.com.

huangapple
  • 本文由 发表于 2023年3月3日 20:03:00
  • 转载请务必保留本文链接：https://go.coder-hub.com/75626824.html
  • automation
  • network-programming
  • pattern-matching
  • python
  • regex
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