英文:
Passing multiple arguments to a function with a dictionary
问题
我有一组函数fun1，fun2，fun3，我从一个主文件中调用它们。它们每个都使用在主文件中存储的一些变量（我也在那里调用这些函数）：
a = 2
b = 3
c = 12
d = "abc"
e = 12
f = "jh4jer"
g = np.array([2, 3])
fun1(a, b, c, d, e, f)
fun2(d, e, f, g)
fun3(a, e, f, g)
我想创建一种结构（在我看来，字典是完美的）来存储所有的变量，所以我可以只传递这个字典给我的函数，就像这样：
dictionary1 = {'a': a, 'b': b, 'c': c, 'd': d, 'e': e, 'f': f, 'g': g}
fun1(dictionary1)
fun2(dictionary1)
fun3(dictionary1)
我可以这样做吗？还是有更聪明的方法？如果我传递给函数的参数多于所需的参数，会有问题吗？
英文:
I have a set of functions fun1, fun2, fun3 that I'm calling from a main file. Each of them are using some variables stored in my main file (where I'm also calling the functions):
a = 2
b = 3
c = 12
d = "abc"
e 12
f = "jh4jer"
g = np.array(2,3)
fun1(a,b,c,d,e,f)
fun2(d,e,f,g)
fun3(a,e,f,g)
I would like to create a sort of structure (in my opinion a dictionary would be perfect) to store all my variables to I can pass only this dictionary to my functions, something like that:
dictionary1 = {'a':a, 'b':b, 'c':c, 'd':d, 'e':e, 'f':f, 'g':g}
fun1(dictionary1)
fun2(dictionary1)
fun3(dictionary1)
Can I do something like that or there is a smarter way? Is it going to be an issue if I pass more arguments to a function with respect to the ones required?
答案1
得分: 1
你可以将整个字典传递给每个函数，然后在函数中只提取它需要的参数。例如：
var1 = 123
var2 = 'hello'
var3 = 456
d = {'a': var1, 'b': var2, 'c': var3}
def func1(x):
print(x['a'])
print(x['c'])
def func2(z):
print(z['b'])
func1(d)
func2(d)
英文:
You can pass the whole dictionary to each function and just pick up in a function the arguments it requires. For example:
var1 = 123
var2 ='hello'
var3 = 456
d = {'a': var1, 'b': var2, 'c': var3}
def func1(x):
print(x['a'])
print(x['c'])
def func2(z):
print(z['b'])
func1(d)
func2(d)
答案2
得分: 0
你可以尝试这种方式 -
obj: dict = {
"a": 2, "b": 3, "c": 12, "d": "abc", "e": 12, "f": "jh4jer", "g": np.array(2,3)}
# 将整个对象传递给函数
fun1(obj)
# 仅向fun2传递所需的变量
fun2_obj = {"d": obj["d"], "e": obj["e"], "f": obj["f"], "g": obj["g"]}
fun2(fun2_obj)
# 仅向fun3传递所需的变量
fun3_obj = {"a": obj["a"], "e": obj["e"], "f": obj["f"], "g": obj["g"]}
fun3(fun3_obj)
英文:
You can try this way -
obj: dict = {
"a": 2, "b": 3, "c": 12, "d": "abc", "e": 12, "f": "jh4jer", "g": np.array(2,3)}
# pass full object to function
fun1(obj)
# pass only required variables to fun2
fun2_obj = {"d": obj["d"], "e": obj["e"], "f": obj["f"], "g": obj["g"]}
fun2(fun2_obj)
# pass only required variables to fun3
fun3_obj = {"a": obj["a"], "e": obj["e"], "f": obj["f"], "g": obj["g"]}
fun3(fun3_obj)
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