传递字典形式的多个参数给函数

huangapple
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英文:

Passing multiple arguments to a function with a dictionary

问题

我有一组函数fun1，fun2，fun3，我从一个主文件中调用它们。它们每个都使用在主文件中存储的一些变量（我也在那里调用这些函数）：

  1. a = 2
  2. b = 3
  3. c = 12
  4. d = "abc"
  5. e = 12
  6. f = "jh4jer"
  7. g = np.array([2, 3])
  9. fun1(a, b, c, d, e, f)
  10. fun2(d, e, f, g)
  11. fun3(a, e, f, g)

我想创建一种结构（在我看来，字典是完美的）来存储所有的变量，所以我可以只传递这个字典给我的函数，就像这样：

  1. dictionary1 = {'a': a, 'b': b, 'c': c, 'd': d, 'e': e, 'f': f, 'g': g}
  2. fun1(dictionary1)
  3. fun2(dictionary1)
  4. fun3(dictionary1)

我可以这样做吗？还是有更聪明的方法？如果我传递给函数的参数多于所需的参数，会有问题吗？

英文:

I have a set of functions fun1, fun2, fun3 that I'm calling from a main file. Each of them are using some variables stored in my main file (where I'm also calling the functions):

  1. a = 2
  2. b = 3
  3. c = 12
  4. d = "abc"
  5. e 12
  6. f = "jh4jer"
  7. g = np.array(2,3)
  9. fun1(a,b,c,d,e,f)
  10. fun2(d,e,f,g)
  11. fun3(a,e,f,g)

I would like to create a sort of structure (in my opinion a dictionary would be perfect) to store all my variables to I can pass only this dictionary to my functions, something like that:

  1. dictionary1 = {'a':a, 'b':b, 'c':c, 'd':d, 'e':e, 'f':f, 'g':g}
  2. fun1(dictionary1)
  3. fun2(dictionary1)
  4. fun3(dictionary1)

Can I do something like that or there is a smarter way? Is it going to be an issue if I pass more arguments to a function with respect to the ones required?

答案1

得分: 1

你可以将整个字典传递给每个函数，然后在函数中只提取它需要的参数。例如：

  1. var1 = 123
  2. var2 = 'hello'
  3. var3 = 456
  5. d = {'a': var1, 'b': var2, 'c': var3}
  7. def func1(x):
  8.     print(x['a'])
  9.     print(x['c'])
  11. def func2(z):
  12.     print(z['b'])
  14. func1(d)
  15. func2(d)
英文:

You can pass the whole dictionary to each function and just pick up in a function the arguments it requires. For example:

  1. var1 = 123
  2. var2 ='hello'
  3. var3 = 456
  5. d = {'a': var1, 'b': var2, 'c': var3}
  7. def func1(x):
  8.     print(x['a'])
  9.     print(x['c'])
  10.     
  11. def func2(z):
  12.     print(z['b'])
  13.         
  14. func1(d)
  15. func2(d)

答案2

得分: 0

你可以尝试这种方式 -

  1. obj: dict = {
  2.     "a": 2, "b": 3, "c": 12, "d": "abc", "e": 12, "f": "jh4jer", "g": np.array(2,3)}
  4. # 将整个对象传递给函数
  5. fun1(obj)
  7. # 仅向fun2传递所需的变量
  8. fun2_obj = {"d": obj["d"], "e": obj["e"], "f": obj["f"], "g": obj["g"]}
  9. fun2(fun2_obj)
  11. # 仅向fun3传递所需的变量
  12. fun3_obj = {"a": obj["a"], "e": obj["e"], "f": obj["f"], "g": obj["g"]}
  13. fun3(fun3_obj)
英文:

You can try this way -

  1. obj: dict = {
  2.     "a": 2, "b": 3, "c": 12, "d": "abc", "e": 12, "f": "jh4jer", "g": np.array(2,3)}
  4. # pass full object to function
  5. fun1(obj)
  7. # pass only required variables to fun2
  8. fun2_obj = {"d": obj["d"], "e": obj["e"], "f": obj["f"], "g": obj["g"]}
  9. fun2(fun2_obj)
  12. # pass only required variables to fun3
  13. fun3_obj = {"a": obj["a"], "e": obj["e"], "f": obj["f"], "g": obj["g"]}
  14. fun3(fun3_obj)

huangapple
  • 本文由 发表于 2023年3月3日 19:28:33
  • 转载请务必保留本文链接：https://go.coder-hub.com/75626520.html
  • python
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