英文:
How to create a loop to write json files with two arguments from difrent lists in python
问题
I would like to modify my code with a for loop for:
- first to create a list of files to create
fnames = [] - secondly to create a list of
json_dics = []
I currently have a separate variable for each file
file_xx = f'{root_path}/{output}/{file_name_xx}.{json_ext}'
and separate variable for each json_dics
json_dic_xx = [{"test": "test", "test1": "test1"}]
I use functions to write data to files
def save_to_json(json_dic, data_to_save):
with open(data_to_save, 'w', encoding='utf_8') as json_file:
json.dump(json_dic, json_file, ensure_ascii=False, indent=4, sort_keys=True)
save_to_json(json_dic_xx, file_xx)
I would like to create a for loop that, using the save_to_json() function, would take two arguments, one from the fnames = [], the other from the json_dics = [], and write the data to the appropriate files accordingly.
EDIT: my solution after making corrections by Rubén Pérez
output_file_names = ['filename01', 'filename02', 'filename03']
fnames = []
for fname in output_file_names:
fnames.append(f'{root_path}/{output}/{fname}.{json_ext}')
json_dics = [[] for _ in range(len(fnames))]
for i in range(len(fnames)):
save_to_json(json_dics[i], fnames[i])
英文:
I would like to modify my code with a for loop for:
- first to create a list of files to create
fnames = [] - secondly to create a list of
json_dics = []
I currently have a separate variable for each file
file_xx = f'{root_path}/{output}/{file_name_xx}.{json_ext}'
and separate variable for each json_dics
json_dic_xx = [{"test": "test", "test1" : "test1"}]
I use functions to write data to files
def save_to_json(json_dic, data_to_save):
with open(data_to_save, 'w', encoding= utf_8) as json_file:
json.dump(json_dic, json_file, ensure_ascii= False, indent=4, sort_keys= True)
save_to_json(json_dic_xx, file_xx)
I would like to create a for loop that, using the save_to_json() function, would take two arguments, one from the fnames = [], the other from the json_dics = [], and write the data to the appropriate files accordingly.
EDIT: my solution after making corrections by Rubén Pérez
output_file_names = ['filename01', `filename02', 'filename03']
fnames = []
for fname in output_file_names:
fnames.append(f'{root_path}/{output}/{fname}.{json_ext}')
json_dics = [[] for _ in range(len(fnames))]
for i in range(len(fnames)):
save_to_json(json_dics[i], fnames[i])
答案1
得分: 1
for i in range(xx):
save_to_json(json_dics[i], fnames[i])
EDIT: You can also create a loop for the first lines:
Assume you have every file_name_xx in a list filenames = [].
fnames = []
for filename in filenames:
fnames.append(f'{root_path}/{output}/{filename}.{json_ext}')
You can do the same with json_dic
<details>
<summary>英文:</summary>
for i in range(xx):
save_to_json(json_dics[i], fnames[i])
EDIT: You can also create a loop for the first lines:
Assume you have every `file_name_xx` in a list `filenames = []`.
fnames = []
for filename in filenames:
fnames.append(f'{root_path}/{output}/{filename}.{json_ext}')
You can do the same with json_dic
</details>
# 答案2
**得分**: 0
你可以使用zip()函数来同时迭代json_dics列表，这将有助于处理。以下是一个示例：
```python
json_dics = [json_dic_01, json_dic_02, json_dic_03, json_dic_04, json_dic_05, json_dic_06, json_dic_07]
fnames = [file_01, file_02, file_03, file_04, file_05, file_06, file_07]
for json_dic, fname in zip(json_dics, fnames):
save_to_json(json_dic, fname)
英文:
You can use zip() function to iterate over both the json_dics list as it will help with that. Below is an example:
json_dics = [json_dic_01, json_dic_02, json_dic_03, json_dic_04, json_dic_05, json_dic_06, json_dic_07]
fnames = [file_01, file_02, file_03, file_04, file_05, file_06, file_07]
for json_dic, fname in zip(json_dics, fnames):
save_to_json(json_dic, fname)
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