英文:
I need help to put a sequential number in the middle of my filenames in LINUX
问题
我有一个目录中的一些文件，我想将它们重命名，以便它们具有顺序。
原始文件名：
Customer_Branch_Record.20230303.1349.DAT
Customer_Branch_Record.20230303.1356.DAT
Customer_Branch_Record.20230303.1527.DAT
我想在文件名之间放置序列01、02、03等，输出如下：
Customer_Branch_Record.01.20230303.1349.DAT
Customer_Branch_Record.02.20230303.1356.DAT
Customer_Branch_Record.03.20230303.1527.DAT
谢谢！
我尝试使用bash进行重命名，但它只能重命名为新名称，而不使用原始详细信息。
#!/bin/bash
a=1
for i in Cust*; do
new=$(printf "Customer_Document_Advices.%02d.txt" "$a") #04 pad to length of 2
mv -i -- "$i" "$new"
let a=a+1
done
输出：
Customer_Document_Advices.02.txt
Customer_Document_Advices.01.txt
Customer_Document_Advices.03.txt
请帮助以这样的方式，我可以在中间放置一个序列，同时保留文件名的原始详细信息。
英文:
I have some files in a directory and I want to rename them in such a way they will have sequence.
Original Filenames:
Customer_Branch_Record.20230303.1349.DAT
Customer_Branch_Record.20230303.1356.DAT
Customer_Branch_Record.20230303.1527.DAT
I want to put a sequence 01 02 03 and so on in between the filenames and output below
Customer_Branch_Record.01.20230303.1349.DAT
Customer_Branch_Record.02.20230303.1356.DAT
Customer_Branch_Record.03.20230303.1527.DAT
Thanks!
I tried bash to rename but it can only rename into a new name and does not use the original details
#!/bin/bash
a=1
for i in Cust*; do
new=$(printf "Customer_Document_Advices.%02d.txt" "$a") #04 pad to length of 2
mv -i -- "$i" "$new"
let a=a+1
done
OUTPUT:
Customer_Document_Advices.02.txt
Customer_Document_Advices.01.txt
Customer_Document_Advices.03.txt
please help in such a way that I can place a sequence in the middle and still retain the original details of the filename
答案1
得分: 0
使用 Perl 的 rename：
$ rename 's/(\.\d{8})/"." . sprintf("%0.2d", ++$::c) . $1/e' ./Customer*
ls -1
Customer_Branch_Record.01.20230303.1349.DAT
Customer_Branch_Record.02.20230303.1356.DAT
Customer_Branch_Record.03.20230303.1527.DAT
英文:
Using Perl's rename:
$ rename 's/(\.\d{8})/"." . sprintf("%0.2d", ++$::c) . $1/e' ./Customer*
ls -1
Customer_Branch_Record.01.20230303.1349.DAT
Customer_Branch_Record.02.20230303.1356.DAT
Customer_Branch_Record.03.20230303.1527.DAT
答案2
得分: 0
您可以尝试：
a=1
while read -r line; do
echo mv $line $(sed -E "/(\.[^.]*){4,}/ ! s/[^.]*/&.$a/" <<< $line)
let a+=1
done < <(find /path/to/directory -type f -name 'Cust*' -printf '%f\n')
如果输出如预期，去掉 echo 以保存更改。
英文:
You can try;
a=1
while read -r line; do
echo mv $line $(sed -E "/(\.[^.]*){4,}/ ! s/[^.]*/&.$a/" <<< $line)
let a+=1
done < <(find /path/to/directory -type f -name 'Cust*' -printf '%f\n')
If the output is as expected, remove the echo to persist the changes
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