Function doesn’t return true or false ReactJS.

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英文:

Function doesn't return true or false ReactJS

问题

当我调用我的permissionCheck函数时,它不会返回truefalse
permissions状态是完整的。

这是我的代码部分:

const [permissions, setPermissions] = useState({});

const permissionCheck = (permission) => {
    var i;
    for (i = 0; i < permissions.length; i++) {
        if (permissions[i].name === permission) {
            return false;
        } else if (permissions[i].name !== permission) return true;
    }
}

// 结果将设置在隐藏组件上。如果结果为true,它将被隐藏,如果为false,它将被显示
hidden={permissionCheck('TEST')}
英文:

When I call my permissionCheck it doesn't return true or false.
The permissions useState is full.

This is the part of my code:

const [permissions, setPermissions] = useState({});

const permissionCheck = (permission) =&gt;
    {
        var i;
        for (i = 0; i &lt; permissions.length; i++)
        {
            if (permissions[i].name === permission)
            {
                return false;
            } else if (permissions[i].name !== permission) return true;
        }
    }


// the outcome will be set on the hidden component. So if the outcome is true it will be hidden and if it is false it will be shown
hidden={permissionCheck(&#39;TEST&#39;)}

答案1

得分: 0

更改代码如下:

const permissionCheck = (permission) => {
    var i;
    for (i = 0; i < permissions.length; i++) {
        if (permissions[i].name === permission) {
            return false;
        }
    }
    return true; // 现在确保有一个返回值。
}
英文:

It is because you are not returning. If both conditions are not met.

Change

const permissionCheck = (permission) =&gt;
    {
        var i;
        for (i = 0; i &lt; permissions.length; i++)
        {
            if (permissions[i].name === permission)
            {
                return false;
            } else if (permissions[i].name !== permission) return true;
        } 
      // &#128072; There is no default return, so you are not getting any returned value
    }

to

const permissionCheck = (permission) =&gt;
    {
        var i;
        for (i = 0; i &lt; permissions.length; i++)
        {
            if (permissions[i].name === permission)
                return false;
        }
        return true; // &#128072; so now one return is assured.
    }

答案2

得分: 0

尝试遍历一个无法工作的对象

将对象权限更改为数组

const [permissions, setPermissions] = useState([]);

并修改您的函数如下:

const permissionCheck = (permission) => {
    var i;
    for (i = 0; i < permissions.length; i++) {
        if (permissions[i].name === permission) {
            return false;
        }
    }
    return true;
}
英文:

You try to iterate through an object which does not work

Change permissions from object

const [permissions, setPermissions] = useState({});

To array:

const [permissions, setPermissions] = useState([]);

And amend your function as follows:

const permissionCheck = (permission) =&gt;
{
    var i;
    for (i = 0; i &lt; permissions.length; i++)
    {
        if (permissions[i].name === permission)
        {
            return false;
        }
    }
   return true;
}

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  • 本文由 发表于 2023年3月1日 16:22:22
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