英文:
How to remove elements from multiple sublists according to another sublist in Python
问题
I have a list J and removing elements from J according to index. I am trying to remove elements of J[0]=[2, 6, 9, 10] according to index[0]=[0,3]. Now after removing, I have J=[6,9] which should append to create [[2, 6, 9, 10], [6, 9]]. Now it should take [6,9] and remove element according to index[1]=[1]. I present the current and expected outputs.
J=[[2, 6, 9, 10]]index=[[0,3],[1]]u=0for v in range(0,len(index)):new_J = [j for i, j in enumerate(J[u]) if i not in index[v]]J.append(new_J)print(J)
The current output is
[[2, 6, 9, 10], [6, 9], [2, 9, 10]]
The expected output is
[[2, 6, 9, 10], [6, 9], [6]]
英文:
I have a list J and removing elements from J according to index. I am trying to remove elements of J[0]=[2, 6, 9, 10] according to index[0]=[0,3]. Now after removing, I have J=[6,9] which should append to create [[2, 6, 9, 10], [6, 9]]. Now it should take [6,9] and remove element according to index[1]=[1]. I present the current and expected outputs.
J=[[2, 6, 9, 10]]index=[[0,3],[1]]u=0for v in range(0,len(index)):new_J = [j for i, j in enumerate(J[u]) if i not in index[v]]J.append(new_J)print(J)
The current output is
[[2, 6, 9, 10], [6, 9], [2, 9, 10]]
The expected output is
[[2, 6, 9, 10], [6, 9], [6]]
答案1
得分: 1
只需使用您的示例，尝试这样做：```pythonJ=[[2, 6, 9, 10]]index=[[0,3],[1]]u=0for v in range(0,len(index)):new_J = [j for i, j in enumerate(J[-1]) if i not in index[v]]J.append(new_J)print(J)
<details><summary>英文:</summary>Just take your example, try this:```pythonJ=[[2, 6, 9, 10]]index=[[0,3],[1]]u=0for v in range(0,len(index)):new_J = [j for i, j in enumerate(J[-1]) if i not in index[v]]J.append(new_J)print(J)
答案2
得分: 1
你可以使用 itertools.accumulate：
from itertools import accumulateJ = [[2, 6, 9, 10]]idx = [[0,3], [1]]J = list(accumulate(idx, lambda lst, idx: [v for i, v in enumerate(lst) if i not in idx],initial=J[-1]))
[[2, 6, 9, 10], [6, 9], [6]]
英文:
You can apply itertools.accumulate:
from itertools import accumulateJ = [[2, 6, 9, 10]]idx = [[0,3], [1]]J = list(accumulate(idx, lambda lst, idx: [v for i, v in enumerate(lst) if i not in idx],initial=J[-1]))
[[2, 6, 9, 10], [6, 9], [6]]
通过集体智慧和协作来改善编程学习和解决问题的方式。致力于成为全球开发者共同参与的知识库，让每个人都能够通过互相帮助和分享经验来进步。
评论