英文:
Appending the list to the base list in Python
问题
J = [[2, 6, 9, 10]]
index = [[0, 3]]
J = [j for i, j in enumerate(J[0]) if i not in index[0]]
J.append(J)
英文:
I have a list J. I am removing elements according to index but I also want to append the new list to the base list J. I present the current and expected outputs.
J = [[2, 6, 9, 10]]
index = [[0, 3]]
J = [j for i,j in enumerate(J[0]) if i not in index[0]]
print(J.append(J))
The current output is
None
The expected output is
[[2, 6, 9, 10],[6, 9]]
答案1
得分: 0
尝试这个：
J = [[2, 6, 9, 10]]
baseJ = J[0].copy()
index = [[0, 3]]
for i in range(len(index[0])):
baseJ.pop(index[0][i] - i)
J.append(baseJ)
print(J)
英文:
Try this:
J=[[2, 6, 9, 10]]
baseJ = J[0].copy()
index=[[0,3]]
for i in range(len(index[0])):
baseJ.pop(index[0][i] - i)
J.append(baseJ)
print(J)
答案2
得分: 0
如何在for循环中遍历新列表的值？
J = [[2, 6, 9, 10]]
index = [[0, 3]]
for i in index:
J.append(I)
抱歉，如果这不是你想要的！
英文:
How about looping through the values of the new list in a for loop?
J = [[2, 6, 9, 10]]
index = [[0, 3]]
for i in index:
J.append(I)
Sorry if this isn't what you wanted!
答案3
得分: 0
J = [[2, 6, 9, 10]]
index = [0, 3]
new_J = [j for i, j in enumerate(J[0]) if i not in index]
J.append(new_J)
print(J)
英文:
Try this:
J = [[2, 6, 9, 10]]
index = [0, 3]
new_J = [j for i, j in enumerate(J[0]) if i not in index]
J.append(new_J)
print(J)
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