我的网站已被Google Chrome标记为危险。

huangapple go评论60阅读模式
英文:

My website has been marked as dangerous by Google Chrome

问题

最近,我使用Next.js TypeScript和Sanity数据库创建了一个社交媒体应用程序。我将我的网站托管在Replit上。但当我在Google Chrome浏览器中打开它时,它显示"欺诈性网站",原因显示为钓鱼。我不明白为什么Google会显示这样的提示,因为我的应用程序中没有恶意软件,也不会安装任何东西或泄露个人信息。这只是一个简单的渐进式Web应用程序(PWA)。

由于这是一个社交媒体应用程序,它需要收集用户信息以创建帐户,这可能是问题的原因吗?

我尝试联系Google支持,但找不到他们的电子邮件。

英文:

Recently, I made a social media app by using Next.js typescript and sanity database. I hosted my website in replit. But as I opened it in my google chrome browser, it is showing deceptive site ahead and the cause is being shown as phishing. I don't understand why is google showing that as I have no malware inside my app, nor my app starts installing anything or reveal personal information. It is a simple pwa!

As it is social media app, it needs to take user information for creating account, is it the problem?

I tried contacting google support but couldn't find their email.

答案1

得分: 2

https://safebrowsing.google.com/safebrowsing/report_error/?hl=en

英文:

Hey! If you believe your website was incorrectly flagged by Google's Phishing Detection, I provided a link for you below to request a review 我的网站已被Google Chrome标记为危险。

https://safebrowsing.google.com/safebrowsing/report_error/?hl=en

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  • 本文由 发表于 2023年3月1日 13:40:20
  • 转载请务必保留本文链接:https://go.coder-hub.com/75599960.html
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