正则表达式匹配反转

huangapple
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英文:

Regex match reverse

问题

  1. 我有一个字符串
  3. ```yaml
  4.   string: Octane_2022.1.0.6_Houdini_19.5.493_OSX.zip

和目前的正则表达式

  1.   regex_search('[0-9]{2}.[0-9]')

这将获取到 2022。期望的结果是 19.5，无论该字段中包含什么内容。

基本上，我需要始终获取此安装程序的基本版本号。当没有年份时，它运行正常，但如何强制我的正则表达式仅在存在 2 位数字 + "." + 1 位数字时获取它？

  2. <details>
  3. <summary>英文:</summary>
  5. I have a string
  7. ```yaml
  8.   string: Octane_2022.1.0.6_Houdini_19.5.493_OSX.zip

and regex currently

  1.   regex_search(&#39;[0-9]{2}.[0-9]&#39;)

This will get 2022. The expected result is 19.5 whatever is in that field.

Essentially, I need to always gather the base version number of this installer. It works fine when there is no year in there, but how do I force my regex to only get it if it is 2 digits + "." + 1 digit?

答案1

得分: 2

以下是翻译的部分：

  1. 声明变量
  3. ```yaml
  4. version_regex: &#39;^\d{2}\.\d{1}.*$&#39;
  5. version: &quot;{{ string|
  6.            split(&#39;_&#39;)|
  7.            select(&#39;regex&#39;, version_regex)|first }}&quot;
  8. major: &quot;{{ version|split(&#39;.&#39;)|first }}&quot;
  9. major_minor: &quot;{{ version|splitext|first }}&quot;
  10. patch: &quot;{{ version|split(&#39;.&#39;)|last }}&quot;

产生结果

  1. version: 19.5.493
  2. major: 19
  3. major_minor: 19.5
  4. patch: 493

详细信息：

给定字符串

  1. string: Octane_2022.1.0.6_Houdini_19.5.493_OSX.zip

拆分字符串

  1. arr: &quot;{{ string|split(&#39;_&#39;) }}&quot;

产生结果

  1. arr:
  2. - Octane
  3. - 2022.1.0.6
  4. - Houdini
  5. - 19.5.493
  6. - OSX.zip

选择满足 "是2位数字 + '.' + 1位数字" 条件的项目

  1. version: &quot;{{ arr|select(&#39;regex&#39;, version_regex)|first }}&quot;
  2. version_regex: &#39;^\d{2}\.\d{1}.*$&#39;

产生结果

  1. version: 19.5.493

如果版本格式是语义化版本（major.minor.patch），拆分项目

  1. major: &quot;{{ version|split(&#39;.&#39;)|first }}&quot;
  2. major_minor: &quot;{{ version|splitext|first }}&quot;
  3. patch: &quot;{{ version|split(&#39;.&#39;)|last }}&quot;

产生结果

  1. major: 19
  2. major_minor: 19.5
  3. patch: 493

用于测试的完整Playbook示例

  1. - hosts: localhost
  3.   vars:
  5.     string: Octane_2022.1.0.6_Houdini_19.5.493_OSX.zip
  6.     arr: &quot;{{ string|split(&#39;_&#39;) }}&quot;
  7.     version_regex: &#39;^\d{2}\.\d{1}.*$&#39;
  8.     # version: &quot;{{ arr|select(&#39;regex&#39;, version_regex)|first }}&quot;
  9.     version: &quot;{{ string|
  10.                  split(&#39;_&#39;)|
  11.                  select(&#39;regex&#39;, version_regex)|first }}&quot;
  12.     major: &quot;{{ version|split(&#39;.&#39;)|first }}&quot;
  13.     major_minor: &quot;{{ version|splitext|first }}&quot;
  14.     patch: &quot;{{ version|split(&#39;.&#39;)|last }}&quot;
  15.     # major_minor: &quot;{{ version|split(&#39;.&#39;)[:2]|join(&#39;.&#39;) }}&quot;
  17.   tasks:
  19.     - debug:
  20.         var: arr
  21.     - debug:
  22.         var: version
  24.     - debug:
  25.         msg: |
  26.           major: {{ major }}
  27.           major_minor: {{ major_minor }}
  28.           patch: {{ patch }}


```

英文:

Declare the variables

  1.   version_regex: &#39;^\d{2}\.\d{1}.*$&#39;
  2.   version: &quot;{{ string|
  3.                split(&#39;_&#39;)|
  4.                select(&#39;regex&#39;, version_regex)|first }}&quot;
  5.   major: &quot;{{ version|split(&#39;.&#39;)|first }}&quot;
  6.   major_minor: &quot;{{ version|splitext|first }}&quot;
  7.   patch: &quot;{{ version|split(&#39;.&#39;)|last }}&quot;

gives

  1.   version: 19.5.493
  2.   major: 19
  3.   major_minor: 19.5
  4.   patch: 493

<hr>

<sup>

Details:

Given the string

  1.   string: Octane_2022.1.0.6_Houdini_19.5.493_OSX.zip

Split the string

  1.   arr: &quot;{{ string|split(&#39;_&#39;) }}&quot;

gives

  1.   arr:
  2.   - Octane
  3.   - 2022.1.0.6
  4.   - Houdini
  5.   - 19.5.493
  6.   - OSX.zip

Select the item that "is 2 digits + '.' + 1 digit"

  1.   version: &quot;{{ arr|select(&#39;regex&#39;, version_regex)|first }}&quot;
  2.   version_regex: &#39;^\d{2}\.\d{1}.*$&#39;

gives

  1.   version: 19.5.493

If the version's format is semantic versioning (major.minor.patch) split the items

  1.   major: &quot;{{ version|split(&#39;.&#39;)|first }}&quot;
  2.   major_minor: &quot;{{ version|splitext|first }}&quot;
  3.   patch: &quot;{{ version|split(&#39;.&#39;)|last }}&quot;

gives

  1.     major: 19
  2.     major_minor: 19.5
  3.     patch: 493

Example of a complete playbook for testing

  1. - hosts: localhost
  3.   vars:
  5.     string: Octane_2022.1.0.6_Houdini_19.5.493_OSX.zip
  6.     arr: &quot;{{ string|split(&#39;_&#39;) }}&quot;
  7.     version_regex: &#39;^\d{2}\.\d{1}.*$&#39;
  8.     # version: &quot;{{ arr|select(&#39;regex&#39;, version_regex)|first }}&quot;
  9.     version: &quot;{{ string|
  10.                  split(&#39;_&#39;)|
  11.                  select(&#39;regex&#39;, version_regex)|first }}&quot;
  12.     major: &quot;{{ version|split(&#39;.&#39;)|first }}&quot;
  13.     major_minor: &quot;{{ version|splitext|first }}&quot;
  14.     patch: &quot;{{ version|split(&#39;.&#39;)|last }}&quot;
  15.     # major_minor: &quot;{{ version|split(&#39;.&#39;)[:2]|join(&#39;.&#39;) }}&quot;
  17.   tasks:
  19.     - debug:
  20.         var: arr
  21.     - debug:
  22.         var: version
  24.     - debug:
  25.         msg: |
  26.           major: {{ major }}
  27.           major_minor: {{ major_minor }}
  28.           patch: {{ patch }}

</sup>

答案2

得分: 1

你可以使用这个正则表达式

  1. Octane_(.*(?=\_Houdini))_Houdini_(.*(?=\_))

它将返回两个值的组

  • 年份: 2022.1.0.6
  • 版本: 19.5.493

这个正则表达式是如何工作的

  1. (?=\_)

使用正向预查来匹配你想要的标识符，在这种情况下，第一个组是 _Houdini，第二个组是 _。

英文:

you can use this regex

  1. Octane_(.*(?=\_Houdini))_Houdini_(.*(?=\_))

it will return 2 groups of value

  • year: 2022.1.0.6
  • version: 19.5.493

how this regex works

  1. (?=\_)

using positive lookahead to match the indentifier you want, for this case is _Houdini for 1st group and _ for 2nd group

答案3

得分: 1

We can work backwards by using a lookahead:

  1. (?<=_)\d{2}\.\d(?=\.\d+_[A-Z]+\.zip)

This only matches if preceded by an underscore, then looks for exactly two digits followed by a ".", then by one digit, and it is only matched if proceeded by another dot, one or more digits, an underscore, several capital letters, then the literal ".zip".

Try it.

英文:

We can work backwards by using a lookahead:

  1. (?&lt;=_)\d{2}\.\d(?=\.\d+_[A-Z]+\.zip)

This only matches if preceded by an underscore, then looks for exactly two digits followed by a &quot;.&quot;, then by one digit, and it is only matched if proceeded by another dot, one or more digits, an underscore, several capital letters, then the literal &quot;.zip&quot;.

Try it.

huangapple
  • 本文由 发表于 2023年3月1日 09:33:52
  • 转载请务必保留本文链接：https://go.coder-hub.com/75598839.html
  • ansible
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