英文:
How to plot multiple periods using pyplot?
问题
大家好！
我现在正在学习信号，但在尝试在pyplot中绘制多个周期时遇到了困难。我不确定问题是数学部分还是代码本身的问题。我认为这是一个愚蠢的问题，但任何帮助都将很有帮助！
这是正在绘制的内容：
这是我想要绘制的内容：
英文:
everyone!
I'm learning about signals now, but I'm having a tough time trying to plot more than one period using pyplot. I don't know if the problem is with the mathematical part or with the code itself. I think this is a silly question, but any help would be great!
import numpy as np
import matplotlib.pyplot as plt
def function(t):
return t**2
# Fundamental Period and Frequency:
T = 2*np.pi
w = 2*np.pi/T
# Defining the limits and the x values(in our case, time):
inferior_limit, superior_limit = -np.pi, np.pi
time_values = np.linspace(inferior_limit, superior_limit, 1000)
# Desired function plot:
plt.style.use('bmh')
plt.plot(time_values, function(time_values), color='k')
plt.show()
This is what is begin plot:
And this is what I would like to plot:
答案1
得分: 1
以下是您要翻译的内容：
主要问题在于t²不是一个周期函数。您想要的函数的图形是(((t + π) % (2π)) - π)^2（图表）。
您可以在function函数中实现如下：
def function(t):
return (((t + np.pi) % (2*np.pi)) - np.pi)**2
只需更改这部分代码，应该得到以下输出：
英文:
The main problem here is that t² is not a periodic function. The graph of the function you want is (((t + π) % (2π)) - π)² (graph).
You can implement that in the function function as:
def function(t):
return (((t + np.pi) % (2*np.pi)) - np.pi)**2
Just changing that should give the output:
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