调试Perl循环以将数据存储到引用数组。

huangapple go评论50阅读模式
英文:

debug Perl loop to store data to a reference array

问题

以下是您提供的代码的翻译部分:

我有一段像这样的代码

      foreach my $l(@inarray){
            chop($l);
            if($flag == 0 && $l =~ /^start /){
                my @array01 = split(/\(/,$l);
                $module_name = $array01[0];
                my @array03 = split(/\s/,$array01[-1]);
                $local_data{"module_name"} = $module_name;
                $local_data{"variables"} = \@array03;   
                $flag = 1;
            }
            if($flag == 1 && $l =~ /input/){
                chop($l);
                $l =~ s/input\s+//g;
                my @array01 = split(/,\s/,$l);
                $local_data->{"input"} = \@array01;
            }
    
            if($flag == 1 && $l =~ /output/){
                chop($l);
                $l =~ s/output\s+//g;
                my @array01 = split(/,\s/,$l);
                $local_data->{"output"} = \@array01;
            }
            if($flag == 1 && $l =~ /end/){         
                push @$infos, $local_data;
                $flag = 0;      
            }
             
    }

但是当我打印@$infos数组时我看到数组的所有元素都与最后一个元素相同它们应该是不同的因为我正在使用标志来分隔它们我不确定为什么会发生这种情况
英文:

I have a piece of code like this

  foreach my $l(@inarray){
        chop($l);
        if($flag == 0 && $l =~ /^start /){
            my @array01 = split(/\(/,$l);
            $module_name = $array01[0];
            my @array03 = split(/\s/,$array01[-1]);
            $local_data{"module_name"} = $module_name;
            $local_data{"variables"} = \@array03;   
            $flag = 1;
        }
        if($flag == 1 && $l =~ /input/){
            chop($l);
            $l =~ s/input\s+//g;
            my @array01 = split(/,\s/,$l);
            $local_data->{"input"} = \@array01;
        }

        if($flag == 1 && $l =~ /output/){
            chop($l);
            $l =~ s/output\s+//g;
            my @array01 = split(/,\s/,$l);
            $local_data->{"output"} = \@array01;
        }
        if($flag == 1 && $l =~ /end/){         
            push @$infos, $local_data;
            $flag = 0;      
        }
         
}

but when I print the @$infos array I saw all the elements of the array are the same as the last element, they are supposed to be different because I'm using the flag to separate them. I'm not sure why this is happening.

答案1

得分: 3

这段代码中只有一个(全局的)$local_data,所以相同的对象一直被添加到@$infos中。我认为你希望每次遇到end标记时重置$local_data

push @$infos, $local_data;
$local_data = {};   # 或者 $local_data = LocalDataThing->new()

或者你可以每次都轻松添加$local_data的(浅)拷贝。

push @$infos, {%$local_data};
英文:

There is only one (global) $local_data in this code, so the same object keeps getting appended to @$infos. I think you want to reset $local_data each time you encounter the end token.

push @$infos, $local_data;
$local_data = {};   # or  $local_data = LocalDataThing->new()

Or you could easily append a (shallow) copy of $local_data each time.

push @$infos, {%$local_data};

huangapple
  • 本文由 发表于 2023年2月27日 11:00:15
  • 转载请务必保留本文链接:https://go.coder-hub.com/75576434.html
匿名

发表评论

匿名网友

:?: :razz: :sad: :evil: :!: :smile: :oops: :grin: :eek: :shock: :???: :cool: :lol: :mad: :twisted: :roll: :wink: :idea: :arrow: :neutral: :cry: :mrgreen:

确定