Regex expression to find number sequence?

I am trying to use regex to return the ticket number from the following body of text:

TICKET #IM40135514 OPENED

In this case, would return

IM40133514

I am not sure what the proper regex expression would be. I tried

number=re.findall("TICKET (\w{2}d{7}+))", filetext)

but keep getting an error.

Using re.findall should be fine here:

<!-- language: python -->

inp = "TICKET #IM40135514 OPENED"
nums = re.findall(r'\bTICKET #(\S+)', inp)
print(nums)  #['IM40135514']

Note that I am using a raw string for the regex pattern, which is indicated with a prefix of r.

Regex is not required here. You can just split() the text by a space, grab the middle string, and remove the "#".

s = "TICKET #IM40135514 OPENED"
ticket = s.split()[1].replace("#", "")
print(ticket)

and the ticket # is returned,

IM40135514

There's a few things wrong with your expression.

1. Unless using a raw string, you'll need to double escape so that the regex engine gets the full escape sequence. r"\w" is equivalent to "\\w".
2. You're missing a # in your expression.
3. You need to escape the d in \w{2}\d{7}.
4. The + means it repeats one or more times and doesn't compile after {7} like that.

Recommend using regex101.com to build your expressions as it breaks them down and explains them to you.

The expression r"TICKET #(\w{2}\d{7})" closely matches what you had and might work for you. Note that \w matches numbers as well so if you specifically want letters, you can use [a-zA-Z]{2}.