英文:
Delete all the folders that are older than two days from a list of folders
问题
以下是您要的翻译部分：
我有三个文件夹。我需要 Ansible 检查它们并删除两天前的那个（或那些）。
以下是我的任务：
- name: 获取较旧文件的路径
find:
paths: "{{ path }}/DB/{{ item }}/"
age: 2d
file_type: directory
recurse: yes
register: filesolderthan2
with_items:
- "{{ bucket }}"
- name: 删除较旧的文件
file:
path: item.path
state: absent
with_items: "{{ filesolderthan2.results }}"
变量文件：
bucket:
- test1
- test2
- test3
path: "/backup"
我成功获取了路径，但无法删除所有这些文件夹。当我尝试使用：
path: {{ item.path }}
时，我遇到了字典错误。
英文:
I have three folders. I need Ansible to check them and delete the one(s) older than two days.
Those are my tasks:
- name: Get older files path
find:
paths: "{{ path }}/DB/{{ item }}/"
age: 2d
file_type: directory
recurse: yes
register: filesolderthan2
with_items:
- "{{ bucket }}"
- name: Remove older files
file:
path: item.path
state: absent
with_items: "{{ filesolderthan2.results }}"
Variable file
bucket:
- test1
- test2
- test3
path: "/backup"
I did get the path but was not able to delete all those folders.
When I tried to use
path: {{ item.path }}
I get dict error
答案1
得分: 3
The find module will list you all the files matched in a files field of a dictionary.
Since you are registering under a loop, you have a results field on top of those multiple files field.
So, what you can do is to use a couple of map and flatten filters to get all those files:
- name: 移除旧文件
file:
path: "{{ item.path }}"
state: absent
loop: "{{ filesolderthan2.results | map(attribute='files') | flatten(1) }}"
英文:
The find module will list you all the files matched in a files field of a dictionary.
Since you are registering under a loop, you have a results field on top of those multiple files field.
So, what you can do is to use a couple of map and flatten filters to get all those files:
- name: Remove older files
file:
path: "{{ item.path }}"
state: absent
loop: "{{ filesolderthan2.results | map(attribute='files') | flatten(1) }}"
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