英文:
convert list of multiple json files into a dataframe pandas
问题
以下是您提供的代码和问题的翻译部分：
base_dir = 'jsons_final_folder/'data_list = []for file in os.listdir(base_dir):if 'json' in file:json_path = os.path.join(base_dir, file)json_data = pd.read_json(json_path, lines=True)data_list.append(json_data)
我得到了一个看起来像这样的列表
print(data_list)output:[ 00 {"general":{"key":"value","q":"..., 00 {"general":{"key":"value","q":"..., 00 {"general":{"key":"value","q":"..., 00 {"general":{"key":"value","q":"..., 00 {"general":{"key":"value","q":"..., 00 {"general":{"key":"value","q":"..., 00 {"general":{"key":"value","q":"...,] 0
所以这是我的代码来转换DataFrame（数据帧）：
with open("f.csv","w") as f:wr = csv.writer(f)wr.writerow(data_list)
但是我得到了一个类型为pandas.core.frame.DataFrame的DataFrame，像这样：
|{"general":{"key":"value","q":"... | {"general":{"key":"value","q":"... | {"general":{"key":"value","q":"... | {"general":{"key":"value","q":"... ||-------------------------------- | -------------------------------- | -------------------------------- | -------------------------------- || | | | |
具有 n 列和 0 行的形状。
我在尝试将**dilimiter（分隔符）**添加到DataFrame，但是仍然无法获得我想要的结果。
我想要的最终形状是这样的：
| json ||---------------------|| {"general":{"key":"value","q":"... || {"general":{"key":"value","q":"... |
谢谢您。
英文:
This how I parsed multiple json files in a single list
base_dir = 'jsons_final_folder/'data_list = []for file in os.listdir(base_dir):if 'json' in file:json_path = os.path.join(base_dir, file)json_data = pd.read_json(json_path, lines=True)data_list.append(json_data)
And I got a list that look like this
print(data_list)output:[ 00 {"general":{"key":"value","q":"..., 00 {"general":{"key":"value","q":"..., 00 {"general":{"key":"value","q":"..., 00 {"general":{"key":"value","q":"..., 00 {"general":{"key":"value","q":"..., 00 {"general":{"key":"value","q":"..., 00 {"general":{"key":"value","q":"...,] 0
So this is my code to convert df
with open("f.csv","w") as f:wr = csv.writer(f)wr.writerow(data_list)
But I get a df that type pandas.core.frame.DataFrame like this:
| {"general":{"key":"value","q":"..., | {"general":{"key":"value","q":"..., | {"general":{"key":"value","q":"..., | {"general":{"key":"value","q":"..., |
|---|
with shape of n columns and 0 rows
What I am trying to do here is to make a df out of this list that contains only jsons with specific queries but i don't what's the problem.
I also tried to add dilimiter
I wanted the final shape be look like this
| json |
|---|
| {"general":{"key":"value","q":"..., |
| {"general":{"key":"value","q":"..., |
Thank you
答案1
得分: 0
你试过 df = pd.DataFrame({'json': data_list}) 吗？
英文:
Have you tried df = pd.DataFrame({'json': data_list}) ?
答案2
得分: 0
Guys I found the solution from This video
function to return files
def get_files(filepath):all_files = []for root, dirs, files in os.walk(filepath):files = glob.glob(os.path.join(root, '*.json'))for f in files:all_files.append(os.path.abspath(f))return all_files
j_files = get_files("../path goes here/")
Here we read each file and import it into list
j_files_list = []for j_file in j_files:with open(j_file) as doc:exp = json.load(doc)j_files_list.append(exp)
here we convert it into a df
df = pd.DataFrame(j_files_list)
And then save list to csv
df.to_csv('json_files_in_df.csv')
Thanks for helping out
英文:
Guys I found the solution from This video
function to return files
def get_files(filepath):all_files = []for root, dirs, files in os.walk(filepath):files = glob.glob(os.path.join(root,'*.json'))for f in files:all_files.append(os.path.abspath(f))return all_filesj_files = get_files("../path goes here/")
Here we read each file and import it into list
j_files_list = []for j_file in j_files:with open(j_file) as doc:exp = json.load(doc)j_files_list.append(exp)
here we convert it into a df
df = pd.DataFrame(j_files_list)
And then save list to csv
df.to_csv('json_files_in_df.csv')
Thanks for helping out
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