undefined behaviour when trying to print array elements

#include<stdio.h>
int main(){
  char names[3][5]={{'a','b','c','d','\0'},{'e','f','g','h','\0'},{'k','l','m','n','\0'}};
  char (*x)[5];

  for(x=names;x<=x+2;x++){
    printf("%s\n",*x);
  }
}

the goals of this code is to printf the strings in this 2d array, but the output is really weird. It is the first time I see something like this.

ouptut:

> 
> abcd
> efgh
> klmn
> �=3�
> 
> 
> 
> 
> 
> 
> I8V
> 
> 
> 3�
> 
> �
> ��.m�
> �
> 
> ?3�
> 
> zI8V
> 
> 
> ��HU�yԁB��7x
> �yԁB��7x
> B��7x
> 
> 
> 
> 
> 
> 
> 
> �
> 
> ���
> 
> 
> 
> �yI8V
> 
> I8V
> 
> 
> 
> 
> 
> 
> 
> 
> 
> ��p��C�x86_64
> �C�x86_64
> x86_64
> 4
> 
> 
> /strcat
> at
> ELL=/bin/bash
> bin/bash
> ash
> ESSION_MANAGER=local/kali:@/tmp/.ICE-unix/836,unix/kali:/tmp/.ICE-unix/836
> N_MANAGER=local/kali:@/tmp/.ICE-unix/836,unix/kali:/tmp/.ICE-unix/836
> AGER=local/kali:@/tmp/.ICE-unix/836,unix/kali:/tmp/.ICE-unix/836
> local/kali:@/tmp/.ICE-unix/836,unix/kali:/tmp/.ICE-unix/836
> /kali:@/tmp/.ICE-unix/836,unix/kali:/tmp/.ICE-unix/836
> :@/tmp/.ICE-unix/836,unix/kali:/tmp/.ICE-unix/836
> p/.ICE-unix/836,unix/kali:/tmp/.ICE-unix/836
> E-unix/836,unix/kali:/tmp/.ICE-unix/836
> x/836,unix/kali:/tmp/.ICE-unix/836
> ,unix/kali:/tmp/.ICE-unix/836
> /kali:/tmp/.ICE-unix/836
> :/tmp/.ICE-unix/836
> /.ICE-unix/836
> -unix/836
> /836
> WINDOWID=0
> WID=0
> 
> CCESSIBILITY=1
> IBILITY=1
> TY=1
> COLORTERM=truecolor
> TERM=truecolor
> truecolor
> olor
> XDG_CONFIG_DIRS=/etc/xdg
> ONFIG_DIRS=/etc/xdg
> _DIRS=/etc/xdg
> =/etc/xdg
> /xdg
> XDG_SESSION_PATH=/org/freedesktop/DisplayManager/Session0
> ESSION_PATH=/org/freedesktop/DisplayManager/Session0
> N_PATH=/org/freedesktop/DisplayManager/Session0
> H=/org/freedesktop/DisplayManager/Session0
> g/freedesktop/DisplayManager/Session0
> edesktop/DisplayManager/Session0
> top/DisplayManager/Session0
> isplayManager/Session0
> yManager/Session0
> ger/Session0

Could you explain the meaning of that output and why am I getting it?

edit

Now I understand where I made the mistake, but anyway I want to know where does that output come.

#include <stdio.h>

int main(){
    char names[3][5] = {{'a','b','c','d','\0'},{'e','f','g','h','\0'},{'k','l','m','n','\0'}};
    char (*x)[5];

    //                   +- HERE
    //                   |
    for (x = names; x <= x + 2; x++) {
        printf("%s\n", *x);
    }
}

The problem is that you compare the value of x to itself.
The expression x <= x + 2 can never be false.
The value of x is reevaluated for each occurrence in the expression, not just the left side.
You should store the result of x + 2 in a variable and use that variable on the right side of the expression.

You wondered where those "weird strings" came from. They look like fragments of a typical Unix/Linux process environment, which consists of a list of name/value pairs known as environment variables.

Normally you access these strings in a C program by using the getenv function, but they are contained in an array of strings (similar to your program's arguments argv) copied in to your process's address space when it is exec'ed. Under most Unix-like systems you can peek at the raw environment strings using code like the following:

#include <stdio.h>

int main(int argc, char **argv, char **envp)
{
    char *p;
    for(p = *envp;; p++) putchar(*p);
}

or

extern char **environ;

int main()
{
    char *p;
    for(p = *environ;; p++) putchar(*p);
}

Those are both quickly and crudely written, and sail off the end of the environment and eventually crash (as indeed your program did). A cleaner way of printing the environment would be

char **v;
char *p;
for(v = environ; *v != NULL; v++) {
    for(p = *v; *p != '
char **v;
char *p;
for(v = environ; *v != NULL; v++) {
for(p = *v; *p != '\0'; p++) putchar(*p);
putchar('\n');
}
'; p++) putchar(*p);
    putchar('\n');
}