在MapStruct中设置日期时间字段为当前时间怎么做?

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英文:

Set datetime field now in MapStruct?

问题

我有一个POJO类中的Instant字段,希望在创建记录时将其值设置为 `now()`。据我所见,MapStruct支持这种功能,但我无法正确设置它:

***mapper:***

@Mapper(componentModel = "spring", imports = {Instant.class})
public interface CreatePostRequestMapper {

// @Mapping(target = "createdAt", defaultExpression ="java(Instant.now())")
@Mapping(target = "createdAt", defaultValue = "java(Instant.now())")
Post toEntity(CreatePostRequest source);

CreatePostRequest toDto(Post destination);

}


并且两个类都具有相同名称的相同属性:

private Instant createdAt;


以下是服务方法:

private final CreatePostRequestMapper createPostRequestMapper;

public PostDetails createPost(@Valid CreatePostRequest request) {
final Post post = createPostRequestMapper.toEntity(request);

// 省略的代码

}


这将导致以下错误:

"Request processing failed; nested exception is java.time.format.DateTimeParseException: Text 'java(Instant.now())' could not be parsed at index 0] with root cause"

如何解决这个问题?
英文:

I have an Instant field in my POJO class and want to set its value now() while creating record. As far as I see, MapStruct let this kind of feature, but I could not set it properly:

mapper:

@Mapper(componentModel = "spring", imports = {Instant.class})
public interface CreatePostRequestMapper {

    // @Mapping(target = "createdAt", defaultExpression ="java(Instant.now())")
    @Mapping(target = "createdAt", defaultValue = "java(Instant.now())")
    Post toEntity(CreatePostRequest source);

    CreatePostRequest toDto(Post destination);
}

And both classes has the same property with the same name:

private Instant createdAt;

Here is the service method:

private final CreatePostRequestMapper createPostRequestMapper;

public PostDetails createPost(@Valid CreatePostRequest request) {
    final Post post = createPostRequestMapper.toEntity(request);

    // code omitted
}

This gives the following error:

"Request processing failed; nested exception is java.time.format.DateTimeParseException: Text 'java(Instant.now())' could not be parsed at index 0] with root cause"

How can solve this?

答案1

得分: 0

当您在Instant类中使用defaultValue时,它将生成以下代码:

post.setCreatedAt( Instant.parse( "java(Instant.now())" ) );

显然,Instant类无法解析这个字符串并创建一个对象。

所以,正确的方式是使用defaultExpression,这将生成以下代码:

post.setCreatedAt( Instant.now() );

区别是显而易见的 在MapStruct中设置日期时间字段为当前时间怎么做?

希望这对您有所帮助。

英文:

When you use defaultValue for Instant class, it will generate following code:

post.setCreatedAt( Instant.parse( "java(Instant.now())" ) );

And, obviously, Instant class cannot parse this string and create an object.

So, the right way is to use defaultExpression, this will generate following code:

post.setCreatedAt( Instant.now() );

The difference is noticeable 在MapStruct中设置日期时间字段为当前时间怎么做?

Hope it will help you.

huangapple
  • 本文由 发表于 2023年2月26日 19:06:54
  • 转载请务必保留本文链接:https://go.coder-hub.com/75571542.html
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