英文:
Getting error while popping in dictionary python
问题
以下是翻译好的部分：
我有一个字典price={'10MAR23': 113.49999999999999,'3MAR23': 19.10000000000001,'25FEB23': 19.100000000000012,'28APR23': 3.5,'26FEB23': 0.4,'31MAR23': 27.5,'17MAR23': 3.1}我想用格式为%d%m%y的相应日期替换键100323030323250223280423260223310323170323以下代码可以实现这一点for i in price:new_key=datetime.datetime.strptime(i,'%d%b%y').strftime('%d%m%y')price[new_key]=price.pop(i)但出现以下错误ValueError: time data '030323' does not match format '%d%b%y'
英文:
I have a dictionary
price={'10MAR23': 113.49999999999999,'3MAR23': 19.10000000000001,'25FEB23': 19.100000000000012,'28APR23': 3.5,'26FEB23': 0.4,'31MAR23': 27.5,'17MAR23': 3.1}
I want to replace the keys with respective dates with format as %d%m%y like
100323030323250223280423260223310323170323
The following code does that,
for i in price:new_key=datetime.datetime.strptime(i,'%d%b%y').strftime('%d%m%y')price[new_key]=price.pop(i)
but getting error like
ValueError: time data '030323' does not match format '%d%b%y'
答案1
得分: 3
这是因为您在循环时同时修改了price的键。您可以通过在执行循环之前复制字典来避免这种情况，如下所示：
price = {'10MAR23': 113.49999999999999,'3MAR23': 19.10000000000001,'25FEB23': 19.100000000000012,'28APR23': 3.5,'26FEB23': 0.4,'31MAR23': 27.5,'17MAR23': 3.1}for i in dict(price):new_key = datetime.datetime.strptime(i, '%d%b%y').strftime('%d%m%y')price[new_key] = price.pop(i)
或者，您可以使用字典推导式从旧字典中创建一个新字典：
price = {datetime.datetime.strptime(k, '%d%b%y').strftime('%d%m%y'): vfor k, v in price.items()}
英文:
This happens because you are looping over price while modifying its keys at the same time. You can avoid that by copying the dictionary before performing the loop, with for i in dict(price):, as so:
price = {'10MAR23': 113.49999999999999,'3MAR23': 19.10000000000001,'25FEB23': 19.100000000000012,'28APR23': 3.5,'26FEB23': 0.4,'31MAR23': 27.5,'17MAR23': 3.1}for i in dict(price):new_key = datetime.datetime.strptime(i,'%d%b%y').strftime('%d%m%y')price[new_key] = price.pop(i)
Alternatively, you can create a new dictionary from the old one with a dictionary comprehension
price = {datetime.datetime.strptime(k, '%d%b%y').strftime('%d%m%y'): vfor k, v in price.items()}
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