英文:
How to create a nested list in python by appending to an existing list
问题
以下是代码部分的翻译，其他内容将被省略：
for i in range(0, len(address_list):# 一些代码被跳过，其中 file_path_simple 每次都会获得新的值with open(file_path_simple, 'r') as fp:for ln in fp:ln = ln.strip('\n')temp_list.append(ln)fp.close()for j in temp_list:address_list[i].append(j)
这是导致错误的代码部分：
Traceback (most recent call last): File "[path_redacted]\tracer.py", line 155, in <module>address_list[i].append([])AttributeError: 'str' object has no attribute 'append'
完整的代码很长，但希望这部分能够提供更好的理解：
address_list = []temp_list = []G = nx.Graph()address_list.append(address)# 添加根节点G.add_node(address_list[0])for i in range(0, len(address_list)):# 用于测试的打印语句print(address_list[i])if i == target:tracePath(address, address_list[i])# 查询地址txQuery(address_list[i])parser()# 将输出写入 temp_list，它将成为嵌套列表file_path_simple = r'Z:\[path_redacted]\tx_list_simple.txt'with open(file_path_simple, 'r') as fp:for ln in fp:ln = ln.strip('\n')temp_list.append(ln)fp.close()# 创建与关联地址的嵌套列表address_list[i].append([])for j in temp_list:address_list[i].append(j)# 创建父节点的子节点，该父节点已被查询for i in address_list[0][i]:G.add_node(i)G.add_edge(*[address_list[0], i])address_list.append(i)temp_list.clear()
英文:
I have a list called address_list and I want to iterate through it. Each value in the address_list I iterate through is run through another function which will return a new list called temp_list. I then want to nest the values of temp_list under the original value in address_list before moving on and doing the same thing to the next value in address_list.
Essentially it should look like this (with the address_list index on the left and the temp_list on the right):
[0] - [1,2,3]
[1] - [1,5,6,7,8,35]
[2] - [3,543,34,84,3,8,53]
This is the code I am trying to use:
for i in range(0,len(address_list)):#some code skipped where file_path_simple gets new values each timewith open(file_path_simple, 'r') as fp:for ln in fp:ln = ln.strip('\n')temp_list.append(ln)fp.close()for j in temp_list:address_list[i].append(j)
This is giving me the following error:
Traceback (most recent call last): File "z:[path_redacted]\tracer.py", line 155, in <module>address_list[i].append([])AttributeError: 'str' object has no attribute 'append'
The full code is LONG but hopefully this chunk will give a better idea:
address_list = []temp_list = []G = nx.Graph()address_list.append(address)#adds the rootG.add_node(address_list[0])for i in range(0,len(address_list)):#print for testing purposesprint(address_list[i])if i == target:tracePath(address, address_list[i])#query the addresstxQuery(address_list[i])parser()#write output to temp_list which will be the nested listfile_path_simple = r'Z:\[path_redacted]\tx_list_simple.txt'with open(file_path_simple, 'r') as fp:for ln in fp:ln = ln.strip('\n')temp_list.append(ln)fp.close()#create the nested list for associated addressesaddress_list[i].append([])for j in temp_list:address_list[i].append(j)#create the children of the parent node which was queriedfor i in address_list[0][i]:G.add_node(i)G.add_edge(*[address_list[0],i])address_list.append(i)temp_list.clear()
答案1
得分: 1
从我了解的情况来看，您想要将文件读入一个列表，然后将该列表放入另一个列表中？您不需要在循环中执行这个操作。
但是，您仍然可以在address_list从该文件中填充后之后循环遍历它。
G = nx.Graph()G.add_node(address)address_list = []file_path_simple = r'Z:\[path_redacted]\tx_list_simple.txt'with open(file_path_simple, 'r') as fp:temp_list = [ln.strip('\n') for ln in fp]address_list.append(temp_list)for i, a in enumerate(address_list):if i == target:tracePath(address, a)# query the addresstxQuery(a)parser()
英文:
From what I can tell, you want to read a file into a list, then put that list into another one? You don't need to do that in a loop
But you can still loop over the address_list after it is populated from that file
G = nx.Graph()G.add_node(address)address_list = []file_path_simple = r'Z:\[path_redacted]\tx_list_simple.txt'with open(file_path_simple, 'r') as fp:temp_list = [ln.strip('\n') for ln in fp]address_list.append(temp_list)for i, a in enumerate(address_list):if i == target:tracePath(address, a)# query the addresstxQuery(a)parser()
答案2
得分: 0
如果我理解正确，您想用temp_list替换值i处的元素？
如果是这样，以下是一些代码（未经测试）：
代码1：
for i, _ in enumerate(address_list):"""enumerate将您的列表转换为一个包含索引和值的元组的列表 -> enumerate(["a", "b", "c"]) == [(0, "a"), (1, "b"), (2, "c")]"""temp_list = [] # 我认为您不需要保留旧值with open(file_path_simple, 'r') as fp:for ln in fp:ln = ln.strip('\n')temp_list.append(ln)# 不需要关闭文件，因为在“with”语句结束时，文件会自动关闭address_list[i] = [] # 用列表替换旧值，这样您就可以进行附加for j in temp_list:address_list[i].append(j)
（未经测试）代码2：
for i, _ in enumerate(address_list):temp_list = []with open(file_path_simple, 'r') as fp:for ln in fp:ln = ln.strip('\n')temp_list.append(ln)address_list[i] = temp_list
不要担心我的英语水平，
Flayme
英文:
If I understand, you wan't to replace the element at the value i by temp_list?
If it's that here is some code (not tested):
code 1:
for i, _ in enumerate(address_list):"""enumerate take your list and transform it into a list contening a tuple contening the index and the value -> enumerate(["a", "b", "c"]) == [(0, "a"), (1, "b"), (2, "c")]"""temp_list = [] # I think you don't need to have the old valuewith open(file_path_simple, 'r') as fp:for ln in fp:ln = ln.strip('\n')temp_list.append(ln)# don't need to close because at the end of the "with" statement#the file is automaticly closeaddress_list[i] = [] # replace the old value by a list so you can#appendfor j in temp_list:address_list[i].append(j)
(not tested) code 2:
for i, _ in enumerate(address_list):temp_list = []with open(file_path_simple, 'r') as fp:for ln in fp:ln = ln.strip('\n')temp_list.append(ln)address_list[i] = temp_list
don't mind my poor english,
Flayme
通过集体智慧和协作来改善编程学习和解决问题的方式。致力于成为全球开发者共同参与的知识库，让每个人都能够通过互相帮助和分享经验来进步。
评论