英文:
How to deserialize Option<T> where T has a custom deserializer?
问题
I want to create deserialize function for Option<T> where I already have a custom deserializer for T and I want to use that deserializer for T when deserializing Option<T>:
pub fn deserialize(deserializer: D) -> Result<T, D::Error>
{
...
}
That is null in JSON to be deserialized to None and non-null to Some(deserialize(deserializer)?).
How to define:
pub fn deserialize(deserializer: D) -> Result<Option<T>, D::Error>
{
... // What here?
}
英文:
I want to create deserialize function for Option<T> where I already have a custom deserializer for T and I want to use that deserializer for T, when deserializing Option<T>:
pub fn deserialize(deserializer: D) -> Result<T, D::Error>
{
...
}
That is null in JSON to be deserialized to None and non-null to Some(deserialize(deserializer)?).
How to define:
pub fn deserialize(deserializer: D) -> Result<Option<T>, D::Error>
{
... // What here?
}
答案1
得分: -2
创建类型 Wrap：
struct Wrap(T);
为 Wrap 定义 Deserialize。
现在我可以为 T 定义 deserialize 函数，将 Wrap 进行反序列化并解包 T 的值。
英文:
Create type Wrap:
struct Wrap(T);
Define Deserialize for Wrap.
Now I can define the deserialize function for T as deserializing Wrap and unwrapping the value of T.
通过集体智慧和协作来改善编程学习和解决问题的方式。致力于成为全球开发者共同参与的知识库，让每个人都能够通过互相帮助和分享经验来进步。
评论