英文:
inputting a 2D array in python using Nested Loops
问题
你好，以下是翻译好的代码部分：
hello guys I'm new to python and I just wanted to give values to a 2D array using nested loops like how we were doing it in java and etc. but says list index out of range and I don't know how to fix it.
this is my code.
prices= [ [] *8] *20
images= []
for i in range (1,8):
images.append(i)
for page in range (8):
for price in range (20):
prices[page][price].append(input())
我没有在互联网上找到任何相关信息。
<details>
<summary>英文:</summary>
hello guys I'm new to python and I just wanted to give values to a 2D array using nested loops like how we were doing it in java and etc. but says list index out of range and I don't know how to fix it.
this is my code.
prices= [ [] *8] *20
images= []
for i in range (1,8):
images.append(i)
for page in range (8):
for price in range (20):
prices[page][price].append(input())
I didn't found any things in internet abut this.
</details>
# 答案1
**得分**: 0
```python
定义数组
```python
prices = []
images = []
并将其他数组附加到第一个数组中，这将创建一个二维数组。
for i in range(1, 8):
images.append(i)
for page in range(8):
for price in range(20):
prices.append(['test', 1])
print(prices)
print(images)
输出
[['test', 1], ['test', 1], ['test', 1],
['test', 1], ['test', 1], ['test', 1], ['test', 1],
..........
['test', 1], ['test', 1], ['test', 1], ['test', 1],
['test', 1], ['test', 1], ['test', 1], ['test', 1]]
[1, 2, 3, 4, 5, 6, 7]
prices[0][0] -> test
prices[0][1] -> 1
<details>
<summary>英文:</summary>
Define arrays
prices = []
images = []
And append other array in first array, this will create 2D array
for i in range (1,8):
images.append(i)
for page in range (8):
for price in range (20):
prices.append(['test', 1])
print(prices)
print(images)
Output
[['test', 1], ['test', 1], ['test', 1],
['test', 1], ['test', 1], ['test', 1], ['test', 1],
..........
['test', 1], ['test', 1], ['test', 1], ['test', 1],
['test', 1], ['test', 1], ['test', 1], ['test', 1]]
[1, 2, 3, 4, 5, 6, 7]
prices[0][0] -> test
prices0 -> 1
</details>
# 答案2
**得分**: 0
当你使用 `[] * 8]` 这个语句时，它将创建一个包含8个指向相同空列表的引用的列表。这段代码将创建8行，每行包含20个元素。
```python
prices = []
for row in range(8):
rows = []
for col in range(20):
rows.append(input())
prices.append(rows)
输出：
这里添加了一张图片，显示它创建了每行包含20个元素的8行。
英文:
When you use [] *8] this statement it will create a list with 8 references to the same empty list. This piece of code will create 8 rows having 20 elements in each.
prices = []
for row in range(8):
rows = []
for col in range(20):
rows.append(input())
prices.append(rows)
Output:
Here adding the picture which shows it creates 8 rows with 20 elements in each.
答案3
得分: 0
我搜索了很多关于它的信息，并向他们询问，他们告诉我这很容易，我只需使用NumPy库。它完美而简单地完成了我想要的事情。
像这样：
images=[]
for i in range(1,9):
images.append(i)
prices=np.array([])
with open('prices.csv', mode='r') as file:
csvFile=csv.reader(file)
for line in csvFile:
prices = np.append(prices,])
prices = prices.reshape(8,20)
如您所请求，这是翻译好的代码部分。
英文:
I searched and asked a lot about it, and they told me it's so easy, I just had to use NumPy library. it done what I wanted so perfect and easy.
like this:
images=[]
for i in range(1,9):
images.append(i)
prices=np.array([])
with open('prices.csv', mode ='r')as file:
csvFile=csv.reader(file)
for line in csvFile:
prices = np.append(prices,])
prices = prices.reshape(8,20)
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