英文:
How to run 3rd party application from my CLI application written in Golang?
问题
我是新手，对于Golang我还不太熟悉，但幸好我有C语言的知识，所以我可以在现有的遗留代码基础上进行一些功能开发。
我有一个基于命令行界面的Go应用程序。我们还使用自定义命令与该应用程序进行交互，例如：
./my_app -s /dev/ttyACM0 -b 115200 init（通过串行接口打开应用程序）
我的问题是，我有一个第三方应用程序，我给它一些.txt文件作为输入，该应用程序会进行一些转换并输出一个文件。
我想将该应用程序的可执行文件附加到我的应用程序中，并通过我的应用程序与该应用程序进行交互，使用一个新的命令，例如：
./my_app -s /dev/ttyACM0 -b 115200 convert "my_file.txt" "生成的输出文件路径"
我需要类似的主题来给我一个起点。
英文:
I am newbie in Golang but thanks to my C-language knowledge. I could do some feature development on existing legacy code base.
I have a CLI based application written in Go. We are interacting with this app also with custom made command like :
./my_app -s /dev/ttyACM0 -b 115200 init ( opens application via Serial Interface)
My question is, I have a 3rd party application, that am giving some .txt input. This app doing some conversion and outputs a file.
I want to attach this application's executable to my application and interact with that application over my own application with the help of a new command like
./my_app -s /dev/ttyACM0 -b 115200 convert "./my_file.txt" "output path file to be generate"
I need similar topic may give me a starting point.
答案1
得分: 2
go/exec 包处理外部命令的执行。要执行给定的命令，你可以编写如下代码：
package main
import (
"log"
"os/exec"
)
func main() {
cmd := exec.Command("./my_third_party_executable", "-s", "/dev/ttyACM0", "-b", "115200", "convert", "./my_file.txt", "output path file to be generate")
err := cmd.Run()
if err != nil {
log.Fatal(err)
}
}
英文:
The go/exec package handles the execution of external commands. To execute your given command you could write code like this:
package main
import (
"log"
"os/exec"
)
func main() {
cmd := exec.Command("./my_third_party_executable", "-s", "/dev/ttyACM0", "-b", "115200", "convert" "./my_file.txt", "output path file to be generate")
err := cmd.Run()
if err != nil {
log.Fatal(err)
}
}
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