英文:
Shell script to sum number between "nmemb:(" and ")"
问题
cat X | grep -o 'nmemb[^_]*$' | doSumBetweenBracket()
英文:
I have a file called "X" which has a lot of nmemb:(123) , nmemb:(56789) , ....
cat X | grep -o 'nmemb[^_]*$'
output like :
nmemb:(16384)
nmemb:(16384)
nmemb:(16384)
nmemb:(5608)
nmemb:(10776)
nmemb:(16384)
nmemb:(16384)
nmemb:(16384)
nmemb:(16384)
nmemb:(16384)
How can I sum these number between "nmemb:(" & ")" ? like :
cat X | grep -o 'nmemb[^_]*$' | doSumBetweenBracket()
答案1
得分: 2
#### 像这样：
$ grep -oP 'nmemb:\(\K\d+' X | paste -sd '+' | bc
或
grep -oP 'nmemb:\(\K\d+' X | awk '{c+=$1}END{print c}'
或者仅使用`GNU` `awk`（没有管道）
awk '/memb:\([0-9]/{match($0, /[0-9]+/, a);c+=a[0]}END{print c}' X
#### 输出
147456
英文:
Like this:
$ grep -oP 'nmemb:\(\K\d+' X | paste -sd '+' | bc
or
grep -oP 'nmemb:\(\K\d+' X | awk '{c+=$1}END{print c}'
or with GNU awk only (no pipes)
awk '/memb:\([0-9]/{match($0, /[0-9]+/, a);c+=a[0]}END{print c}' X
Output
147456
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