英文:
Transform multiple properties of the same type to List of these properties in data class Kotlin
问题
在我的应用程序中，我从JSON中检索数据，不幸的是，它的格式不允许我直接获得一个列表。如何将我的数据类转换为只包含一个属性：List< Itinerary >，其中包含这10个（或更多）行程？
data class ItineraryData(val itineraries: List<Itinerary>)
JSON数据
"itinerary_data" : {"itinerary_0": {...},"itinerary_1": {...},"itinerary_2": {...},"itinerary_3": {...},"itinerary_4": {...},"itinerary_5": {...},"itinerary_6": {...},"itinerary_7": {...},"itinerary_8": {...},"itinerary_9": {...}}
英文:
In my app I'm retrieving data from json and unfortunately, It is written in such a way, that I can't straight away obtain a list. How can I transform my data class to consist of one property: List< Itinerary > which consists these 10 (or more) itineraries?
data class ItineraryData(val itinerary0: Itinerary,val itinerary1: Itinerary,val itinerary2: Itinerary,val itinerary3: Itinerary,val itinerary4: Itinerary,val itinerary5: Itinerary,val itinerary6: Itinerary,val itinerary7: Itinerary,val itinerary8: Itinerary,val itinerary9: Itinerary),
THE JSON
"itinerary_data" : {"itinerary_0": {...},"itinerary_1": {...},"itinerary_2": {...},"itinerary_3": {...},"itinerary_4": {...},"itinerary_5": {...},"itinerary_6": {...},"itinerary_7": {...},"itinerary_8": {...},"itinerary_9": {...},}</details># 答案1**得分**: 1你不能直接这样做。因为 JSON 中的行程安排不是数组格式，所以你无法直接得到 Kotlin 列表。一个解决方案是将其解析为 `Map<String, Itinerary>`，然后从地图中获取值的列表。```kotlindata class ItinerariesResponse(@Json(name = "itinerary_data")val itineraries: Map<String, Itinerary>)
然后你可以这样获取行程安排的列表：
val response: ItinerariesResponse = yourApiCall()val itineraries = response.itineraries.values
英文:
You can't do that directly. Because the itineraries in the json are not in array format, so you can't get a Kotlin list out of it. One solution is to parse it as a Map<String, Itinerary> and then get the list of values from the map.
data class ItinerariesResponse(@Json(name = "itinerary_data")val itineraries: Map<String, Itinerary>)
Then you can get the list of itineraries like this:
val response: ItinerariesResponse = yourApiCall();val itineraries = response.itineraries.values();
通过集体智慧和协作来改善编程学习和解决问题的方式。致力于成为全球开发者共同参与的知识库，让每个人都能够通过互相帮助和分享经验来进步。
评论