英文:
TicTacToe using 2D array in java
问题
以下是您要翻译的代码部分：
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
char[][] board = {
{'?', '?', '?'},
{'?', '?', '?'},
{'?', '?', '?'}
};
System.out.print("Type any key to play the game and type 'n' to stop the game: ");
String Stop = sc.nextLine();
while(true){
if(Stop.equals("n"))break;
System.out.print("Player" + "[" + "X" + "]: ");
int PlayerX = sc.nextInt();
if(PlayerX == 1){
board[2][0] = 'x';
}
if(PlayerX == 2){
board[2][1] = 'x';
}
if(PlayerX == 3){
board[2][2] = 'x';
}
if(PlayerX == 4){
board[1][0] = 'x';
}
if(PlayerX == 5){
board[1][1] = 'x';
}
if(PlayerX == 6){
board[1][2] = 'x';
}
if(PlayerX == 7){
board[0][0] = 'x';
}
if(PlayerX == 8){
board[0][1] = 'x';
}
if(PlayerX == 9){
board[0][2] = 'x';
}
for(char[] x1 : board){
for(char x2 : x1){
System.out.print(x2 + "\t");
}
System.out.println();
}
System.out.print("Player" + "[" + "O" + "]: ");
int PlayerO = sc.nextInt();
if(PlayerO == 1){
board[2][0] = 'o';
}
if(PlayerO == 2){
board[2][1] = 'o';
}
if(PlayerO == 3){
board[2][2] = 'o';
}
if(PlayerO == 4){
board[1][0] = 'o';
}
if(PlayerO == 5){
board[1][1] = 'o';
}
if(PlayerO == 6){
board[1][2] = 'o';
}
if(PlayerO == 7){
board[0][0] = 'o';
}
if(PlayerO == 8){
board[0][1] = 'o';
}
if(PlayerO == 9){
board[0][2] = 'o';
}
for(char[] x1 : board){
for(char x2 : x1){
System.out.print(x2 + "\t");
}
System.out.println();
}
}
}
}
希望这对您有所帮助。如果您有其他问题，请随时提出。
英文:
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
char[][] board = {
{'?','?','?'},
{'?','?','?'},
{'?','?','?'}
};
System.out.print("Type any key to play the game and type 'n' to stop the game: ");
String Stop = sc.nextLine();
while(true){
if(Stop.equals("n"))break;
System.out.print("Player" + "[" + "X" + "]: ");
int PlayerX = sc.nextInt();
if(PlayerX == 1){
board[2][0] = 'x';
}
if(PlayerX == 2){
board[2][1] = 'x';
}
if(PlayerX == 3){
board[2][2] = 'x';
}
if(PlayerX == 4){
board[1][0] = 'x';
}
if(PlayerX == 5){
board[1][1] = 'x';
}
if(PlayerX == 6){
board[1][2] = 'x';
}
if(PlayerX == 7){
board[0][0] = 'x';
}
if(PlayerX == 8){
board[0][1] = 'x';
}
if(PlayerX == 9){
board[0][2] = 'x';
}
for(char[] x1 : board){
for(char x2 : x1){
System.out.print(x2 + "\t");
}
System.out.println();
}
System.out.print("Player" + "[" + "O" + "]: ");
int PlayerO = sc.nextInt();
if(PlayerO == 1){
board[2][0] = 'o';
}
if(PlayerO == 2){
board[2][1] = 'o';
}
if(PlayerO == 3){
board[2][2] = 'o';
}
if(PlayerO == 4){
board[1][0] = 'o';
}
if(PlayerO == 5){
board[1][1] = 'o';
}
if(PlayerO == 6){
board[1][2] = 'o';
}
if(PlayerO == 7){
board[0][0] = 'o';
}
if(PlayerO == 8){
board[0][1] = 'o';
}
if(PlayerO == 9){
board[0][2] = 'o';
}
for(char[] x1 : board){
for(char x2 : x1){
System.out.print(x2 + "\t");
}
System.out.println();
}
}
}
}
I am trying to make a simple TicTacToe program in Java. I am already done in placing the X and O, but I am struggling on checking if there is a winner.
I am confused on what code I will type to check the winner of the program.
答案1
得分: 1
你只需要编写一些代码来检查每一行、列和对角线是否有3个匹配项。你可以利用for循环来更高效地完成这个任务。
public static char checkWinner(char[][] board) {
// 检查行
for (int i = 0; i < 3; i++) {
if (board[i][0] != '?' && board[i][0] == board[i][1] && board[i][1] == board[i][2]) {
return board[i][0];
}
}
// 检查列
for (int j = 0; j < 3; j++) {
if (board[0][j] != '?' && board[0][j] == board[1][j] && board[1][j] == board[2][j]) {
return board[0][j];
}
}
// 检查对角线
if (board[0][0] != '?' && board[0][0] == board[1][1] && board[1][1] == board[2][2]) {
return board[0][0];
}
// 检查反对角线
if (board[0][2] != '?' && board[0][2] == board[1][1] && board[1][1] == board[2][0]) {
return board[0][2];
}
// 无获胜者
return '?';
}
如果你还没有接触过for循环，有很多好的教程可以帮助你，例如 https://www.w3schools.com/java/java_for_loop.asp
（注意，你也可以使用循环来简化你的现有代码）
英文:
You simply just need to write some code to check if there are 3 matches in each row column and diagonal.
You can utilise for loops to do this more efficiently
public static char checkWinner(char[][] board) {
// Check rows
for (int i = 0; i < 3; i++) {
if (board[i][0] != '?' && board[i][0] == board[i][1] && board[i][1] == board[i][2]) {
return board[i][0];
}
}
// Check columns
for (int j = 0; j < 3; j++) {
if (board[0][j] != '?' && board[0][j] == board[1][j] && board[1][j] == board[2][j]) {
return board[0][j];
}
}
// Check diagonal
if (board[0][0] != '?' && board[0][0] == board[1][1] && board[1][1] == board[2][2]) {
return board[0][0];
}
// Check anti-diagonal
if (board[0][2] != '?' && board[0][2] == board[1][1] && board[1][1] == board[2][0]) {
return board[0][2];
}
// No winner
return '?';
}
If you havent come accross for loops yet, there are plenty of good tutorials out there such as https://www.w3schools.com/java/java_for_loop.asp
(Note, you can also use loops to clean up some of your pre-existing code)
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