英文:
Problem with looping in python with pyautogui and keyboard
问题
你的问题是希望通过按下不同的数字键（1、2、3）来执行不同的函数，但执行后程序不退出，继续在后台等待按下其他键。你已经尝试使用线程来执行函数，但在pyautogui.typewrite("111")时遇到了速度问题。
为了解决这个问题，你可以使用pyautogui.hotkey函数来模拟按下键盘上的组合键。这样可以更快速地键入文本。此外，你还可以使用一个循环来持续等待用户按下不同的键。以下是修改后的代码片段：
import threading
import pyautogui
import time
from pynput import keyboard
current = set()
def execute1():
# 你的 execute1 函数代码
# 定义其他的 execute 函数
def on_press(key):
if key == keyboard.KeyCode.from_char('1'):
t = threading.Thread(target=execute1)
t.start()
current.add(key)
# 添加其他键的处理逻辑
def main_loop():
while True:
time.sleep(0.1) # 等待用户按键
if current: # 如果 current 集合非空，表示有按键按下
pass # 执行你想要的操作
def on_release(key):
if key in current:
current.remove(key)
# 启动监听
with keyboard.Listener(on_press=on_press, on_release=on_release) as listener:
main_loop()
通过这种方式，你可以持续等待用户按下不同的键，然后执行相应的操作，而不会退出程序。同时，使用pyautogui.hotkey来模拟按键可以提高键入速度。
英文:
Hello my first time posting, I have a problem with python. So I have this code and it's a keybind like when I press the number 1 i need to execute1() but after this run I don't want the program to exit but just wait and run in the background and wait for another key to be pressed. With this program it keeps looping the execute(). How I can solve this?
import threading
import pyautogui
import time
import pyscreeze
from pynput import keyboard
cmb = [{keyboard.Key.alt_l, keyboard.Key.page_up}] #keybind
current = set()
def execute1():
pyautogui.moveTo(2459,122)
pyautogui.leftClick()
pyautogui.moveTo(2368,392)
pyautogui.leftClick()
pyautogui.moveTo(1542,447)
pyautogui.leftClick()
pyautogui.moveTo(1546,518)
pyautogui.leftClick()
pyautogui.moveTo(1649,635)
pyautogui.leftClick()
pyautogui.moveTo(2018,320)
time.sleep(1.35)
pyautogui.leftClick()
pyautogui.typewrite("111")
pyautogui.moveTo(2006,379)
pyautogui.leftClick()
def execute2():
pyautogui.moveTo(2459,122)
pyautogui.leftClick()
pyautogui.moveTo(2271,505)
pyautogui.leftClick()
pyautogui.moveTo(1542,447)
pyautogui.leftClick()
pyautogui.moveTo(1546,518)
pyautogui.leftClick()
pyautogui.moveTo(1649,635)
pyautogui.leftClick()
pyautogui.moveTo(2018,320)
time.sleep(1.35)
pyautogui.leftClick()
pyautogui.typewrite("111")
pyautogui.moveTo(2006,379)
pyautogui.leftClick()
def execute3():
pyautogui.moveTo(2459,122)
pyautogui.leftClick()
pyautogui.moveTo(2292,603)
pyautogui.leftClick()
pyautogui.moveTo(1542,447)
pyautogui.leftClick()
pyautogui.moveTo(1546,518)
pyautogui.leftClick()
pyautogui.moveTo(1649,635)
pyautogui.leftClick()
pyautogui.moveTo(2018,320)
time.sleep(1.35)
pyautogui.leftClick()
pyautogui.typewrite("111")
pyautogui.moveTo(2006,379)
pyautogui.leftClick()
def on_press(key): #check when key presses
if key == keyboard.KeyCode(char='1'): # check if '1' key is pressed
execute1()
current.add(key)
elif key == keyboard.KeyCode(char='2'): # check if '2' key is pressed
execute2()
current.add(key)
elif key == keyboard.KeyCode(char='3'): # check if '3' key is pressed
execute3()
current.add(key)
def on_release(key): #check when key releases
if any([key in z for z in cmb]):
current.remove(key)
with keyboard.Listener(on_press=on_press, on_release=on_release) as listener:
listener.join()
I tried to do this:
def on_press(key): #check when key presses
if key == keyboard.KeyCode(char='1'): # check if '1' key is pressed
t = threading.Thread(target=execute1)
t.start()
t.join()
current.add(key)
for all the executes but there was another problem, when it reached the pyautogui.typewrite("111") it just typed one of the characters but I wanted to be fast.
This program worked when I had only 1 execution but I want 6 of them now and I can't find a solution
答案1
得分: 0
以下是翻译好的部分：
需要创建一个监听器，但你缺少正确的方式。
以下是一些示例...
当你按下 F7 键时，将鼠标居中显示在屏幕中央：
import pyautogui
import pynput.mouse
import pynput.keyboard
def center_mouse_on_press(key):
if key == pynput.keyboard.Key.f7:
screen_width, screen_height = pyautogui.size()
center_x, center_y = screen_width / 2, screen_height / 2
pyautogui.moveTo(center_x, center_y)
keyboard_listener = pynput.keyboard.Listener(on_press=center_mouse_on_press)
keyboard_listener.start()
keyboard_listener.join()
将鼠标移动到屏幕上的不同位置，具体位置取决于你是否按下 F7, F8 或 F9 键：
import pyautogui
import pynput.mouse
import pynput.keyboard
def move_mouse_on_press(key):
screen_width, screen_height = pyautogui.size()
center_x, center_y = screen_width / 2, screen_height / 2
if key == pynput.keyboard.Key.f7:
pyautogui.moveTo(center_x, center_y/2)
if key == pynput.keyboard.Key.f8:
pyautogui.moveTo(center_x, center_y)
if key == pynput.keyboard.Key.f9:
pyautogui.moveTo(center_x, center_y*2)
keyboard_listener = pynput.keyboard.Listener(on_press=move_mouse_on_press)
keyboard_listener.start()
keyboard_listener.join()
英文:
You need to create a listener, but you are missing the correct way.
Here are a couple of examples...
Center the mouse in the middle of the screen when you press F7:
import pyautogui
import pynput.mouse
import pynput.keyboard
def center_mouse_on_press(key):
if key == pynput.keyboard.Key.f7:
screen_width, screen_height = pyautogui.size()
center_x, center_y = screen_width / 2, screen_height / 2
pyautogui.moveTo(center_x, center_y)
keyboard_listener = pynput.keyboard.Listener(on_press=center_mouse_on_press)
keyboard_listener.start()
keyboard_listener.join()
Move the mouse to different points in the screen depending on whether you press F7, F8 or F9:
import pyautogui
import pynput.mouse
import pynput.keyboard
def move_mouse_on_press(key):
screen_width, screen_height = pyautogui.size()
center_x, center_y = screen_width / 2, screen_height / 2
if key == pynput.keyboard.Key.f7:
pyautogui.moveTo(center_x, center_y/2)
if key == pynput.keyboard.Key.f8:
pyautogui.moveTo(center_x, center_y)
if key == pynput.keyboard.Key.f9:
pyautogui.moveTo(center_x, center_y*2)
keyboard_listener = pynput.keyboard.Listener(on_press=move_mouse_on_press)
keyboard_listener.start()
keyboard_listener.join()
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