Saving the output from Lua in C++ with SOL3 to an std::string

huangapple
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英文:

Saving the output from Lua in C++ with SOL3 to an std::string

问题

我正在尝试将Lua解释器实现到我的C++代码中。我已经使用ImGui为我的项目实现了一个小型编辑器，并将编辑器的输出保存到一个std::vector<char>中。

我的Lua解释器的尝试实现如下：

  1. // 头文件
  2. std::string ExecuteLua();
  3. std::vector<char> m_luaEditorData;
  5. // cpp 文件
  6. std::string Proxy::ExecuteLua()
  7. {
  8.     // 从字符串加载Lua代码
  9.     std::string luaCode(m_luaEditorData.data());
  11.     // 创建Lua状态
  12.     sol::state lua;
  14.     // 加载标准Lua库
  15.     lua.open_libraries(sol::lib::base, sol::lib::package, sol::lib::string, sol::lib::table);
  17.     // 执行Lua代码并存储结果
  18.     sol::protected_function_result result = lua.script(luaCode);
  20.     // 检查错误
  21.     if (!result.valid())
  22.     {
  23.         sol::error error = result;
  24.         std::string errorMsg = error.what();
  25.         return "Lua错误: " + errorMsg;
  26.     }
  28.     // 将结果作为字符串获取
  29.     std::string output = lua["tostring"](result.get<sol::object>());
  31.     // 返回输出
  32.     return output;
  33. }
  35. ...
  37. if (m_luaEditorData.empty())
  38.     m_luaEditorData.push_back('
    // 头文件
  39. std::string ExecuteLua();
  40. std::vector<char> m_luaEditorData;
  42. // cpp 文件
  43. std::string Proxy::ExecuteLua()
  44. {
  45.     // 从字符串加载Lua代码
  46.     std::string luaCode(m_luaEditorData.data());
  48.     // 创建Lua状态
  49.     sol::state lua;
  51.     // 加载标准Lua库
  52.     lua.open_libraries(sol::lib::base, sol::lib::package, sol::lib::string, sol::lib::table);
  54.     // 执行Lua代码并存储结果
  55.     sol::protected_function_result result = lua.script(luaCode);
  57.     // 检查错误
  58.     if (!result.valid())
  59.     {
  60.         sol::error error = result;
  61.         std::string errorMsg = error.what();
  62.         return "Lua错误: " + errorMsg;
  63.     }
  65.     // 将结果作为字符串获取
  66.     std::string output = lua["tostring"](result.get<sol::object>());
  68.     // 返回输出
  69.     return output;
  70. }
  72. ...
  74. if (m_luaEditorData.empty())
  75.     m_luaEditorData.push_back('\0');
  77. auto luaEditorFlags = ImGuiInputTextFlags_AllowTabInput | ImGuiInputTextFlags_CallbackResize;
  78. ImGui::InputTextMultiline("##LuaEditor", m_luaEditorData.data(), m_luaEditorData.size(), ImVec2(ImGui::GetWindowContentRegionWidth(), ImGui::GetWindowHeight() - (ImGui::GetTextLineHeight() * 16), luaEditorFlags, ResizeInputTextCallback, &m_luaEditorData);
  80. ...
  81. ');
  83. auto luaEditorFlags = ImGuiInputTextFlags_AllowTabInput | ImGuiInputTextFlags_CallbackResize;
  84. ImGui::InputTextMultiline("##LuaEditor", m_luaEditorData.data(), m_luaEditorData.size(), ImVec2(ImGui::GetWindowContentRegionWidth(), ImGui::GetWindowHeight() - (ImGui::GetTextLineHeight() * 16), luaEditorFlags, ResizeInputTextCallback, &m_luaEditorData);
  86. ...

当我运行这段代码时，我的输出中只会得到nil，正确的输出应该是标准输出（我不希望它输出在这里，而是输出到我的std::string中），当我输入错误的代码时，它会在sol.hpp中抛出异常。我没有找到如何执行此操作的示例，因此我正在尝试自己解决这个问题。

英文:

I'm trying to implement a lua interpreter to my C++ code. I have implemented a small editor for my project using ImGui and I'm saving the output from the editor to an std::vector<char>.

My attempted implementation of my lua interpeter looks like so;

  1. // header
  2. std::string ExecuteLua();
  3. std::vector&lt;char&gt; m_luaEditorData;
  6. // cpp
  7. std::string Proxy::ExecuteLua()
  8. {
  9. 	// Load the Lua code from the string
  10. 	std::string luaCode(m_luaEditorData.data());
  12. 	// Create a Lua state
  13. 	sol::state lua;
  15. 	// Load standard Lua libraries
  16. 	lua.open_libraries(sol::lib::base, sol::lib::package, sol::lib::string, sol::lib::table);
  18. 	// Execute the Lua code and store the result
  19. 	sol::protected_function_result result = lua.script(luaCode);
  21. 	// Check for errors
  22. 	if (!result.valid())
  23. 	{
  24. 		sol::error error = result;
  25. 		std::string errorMsg = error.what();
  26. 		return &quot;Lua error: &quot; + errorMsg;
  27. 	}
  29. 	// Get the result as a string
  30. 	std::string output = lua[&quot;tostring&quot;](result.get&lt;sol::object&gt;());
  32. 	// Return the output
  33. 	return output;
  34. }
  36. ...
  38. 		if (m_luaEditorData.empty())
  39. 			m_luaEditorData.push_back(&#39;\0&#39;);
  41. 			auto luaEditorFlags = ImGuiInputTextFlags_AllowTabInput | ImGuiInputTextFlags_CallbackResize;
  42. 			ImGui::InputTextMultiline(&quot;##LuaEditor&quot;, m_luaEditorData.data(), m_luaEditorData.size(), ImVec2(ImGui::GetWindowContentRegionWidth(), ImGui::GetWindowHeight() - (ImGui::GetTextLineHeight() * 16)), luaEditorFlags, ResizeInputTextCallback, &amp;m_luaEditorData);
  44. ...

When I run this code, I only get nil in my output, the correct output to stdout (don't really want it to output here, but to my std::string and when I put in bad code, it throws an exception in sol.hpp. I didn't really find any examples on how I can do this and I'm therefore am trying to figure this out on my own.

答案1

得分: 1

我通过用自己的print函数替换原来的print函数来解决了这个问题，如下所示：

  1. int print(lua_State* L)
  2. {
  3.     std::string printString = lua_tostring(L, 1);
  4.     g_luaOutput += printString + "\n";
  5.     return 1;
  6. }
  8. std::string Proxy::ExecuteLua()
  9. {
  10.     std::string luaCode(m_luaEditorData.data());
  12.     sol::state lua;
  14.     lua.open_libraries(sol::lib::base, sol::lib::package, sol::lib::string, sol::lib::table, sol::lib::jit);
  16.     lua.set_function("print", print);
  18.     sol::protected_function_result result = lua.script(luaCode);
  19.     ...
  20. }

现在，当我在我的Lua编辑器中调用print函数时，它将不再打印到标准输出(stdout)，而是打印到我的自定义控制台上。

英文:

I was able to solve the problem myself by replacing the print function with my own like so;

  1. int print(lua_State* L)
  2. {
  3. 	std::string printString = lua_tostring(L, 1);
  4. 	g_luaOutput += printString + &quot;\n&quot;;
  5. 	return 1;
  6. }
  8. std::string Proxy::ExecuteLua()
  9. {
  10. 	std::string luaCode(m_luaEditorData.data());
  12. 	sol::state lua;
  14. 	lua.open_libraries(sol::lib::base, sol::lib::package, sol::lib::string, sol::lib::table, sol::lib::jit);
  16. 	lua.set_function(&quot;print&quot;, print);
  18. 	sol::protected_function_result result = lua.script(luaCode);
  19. 	...

When I now call print in my lua editor I will not print to my own console instead of stdout.

huangapple
  • 本文由 发表于 2023年2月19日 06:25:11
  • 转载请务必保留本文链接：https://go.coder-hub.com/75496764.html
  • c++
  • lua
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