finding out if the characters of a string exist in another string with the same order or not using regex in java

i want to write a program in java using REGEX that gets 2 strings from the input ( the first one is shorter than the second one ) and then if the characters of the first string was inside the second string with the same order but they do not need to be next to each other ( it is not substring ) it outputs "true" and if not it outputs "false" here's an example:

example1:

input:

phantom

pphvnbajknzxcvbnatopopoim

output:

true

in the above example it is obvious we can see the word "phantom" in the second string (the characters are in the same order)

example2:

input:

apple

fgayiypvbnltsrgte

output:

false

as you can see apple dos not exists in the second string with the conditions i have earlier mentioned so it outputs false

import java.util.Scanner;

public class Main {
    public static void main(String[] args) {

        Scanner input = new Scanner(System.in);

        String word1 = input.next();

        String word2 = input.next();

        String pattern = "";

        int n = word1.length();

        char[] word1CharArr = word1.toCharArray();

        for ( int i = 0 ; i < n ; i++) {

            pattern += "[:alnum:]" +word1CharArr[i]+"[:alnum:]";

           // pattern += ".*\\b|\\B" +word1CharArr[i]+"\\b|\\B";
        }

        pattern = "^" + pattern + "$";

       // pattern = "(?s)" + pattern + ".*";

       // System.out.println(pattern);

       System.out.println(word2.matches(pattern));
    }
}

here is what i did . i broke my first string to its characters and want to use REGEX before and after each character to determine the pattern. I have searched much about REGEX and how to use it but still i have problem here. the part i have commented comes out from one of my searches but it did not work
I emphasize that i want to solve it with REGEX not any other way.

[:alnum:] isn't a thing. Even if it is, that would match exactly one character, not 'any number, from 0 to infinitely many of them'.

You just want phantom with .* in the middle: ^.*p.*h.*a.*n.*t.*o.*m.*$' is all you need. After all, phantom` 'fits', and so does paahaanaataaoaamaa -

String pattern = word1.chars()
  .mapToObj(c -> ".*" + (char) c)
  .collect(Collectors.joining()) + ".*";

should get the job done.