英文:
TypeScript - Union type from properties decorated with a specific decorator
问题
class Image {
@Attribute()
public id: number;
@Attribute()
public src: string;
public alt: string;
}
// ?? 应该得到 "id", "src"
type ImageAttributes = ExtractAttributes<typeof Image>
英文:
Is it possible to create a generic type, which accepts a class, some of whose properties are decorated with a specific decorator, and create a type out of them
class Image {
@Attribute()
public id: number;
@Attribute()
public src: string;
public alt: string;
}
// ?? Should result in "id", "src"
type ImageAttributes = ExtractAttributes<typeof Image>
答案1
得分: 1
目前还没有指示字段已被装饰的类型指示。与 TypeScript 几乎一样古老的问题1仍然存在。
所以，截止到今天，没有。
1: https://github.com/microsoft/TypeScript/issues/4881
英文:
Currently there is no type indication that a field has been decorated. The open issues on that are almost as old as TS.
So, as of today, no.
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