英文:
Remove all text, character before first bracket and after last bracket
问题
var string = '.,.a,,{Correct Answer Nr.1 : b.) Susan },{Correct Answer Nr.3 : b.) She doesn’t say },.x.b,'
如何删除第一个 { 之前和最后一个 } 之后的所有文本和字符？
我的期望结果是：
{Correct Answer Nr.1 : b.) Susan },{Correct Answer Nr.3 : b.) She doesn’t say }
并删除：.,.a,, and ,.x.b,
英文:
My string :
var string = '.,.a,,{Correct Answer Nr.1 : b.) Susan },{Correct Answer Nr.3 : b.) She doesn’t say },.x.b,'
How can i remove all text, character before first { and after last }?
My desired result :
{Correct Answer Nr.1 : b.) Susan },{Correct Answer Nr.3 : b.) She doesn’t say }
and remove : .,.a,, and ,.x.b,
Thank you
答案1
得分: 1
我们可以尝试以下正则表达式替换:
var string = '.,.a,,{Correct Answer Nr.1 : b.) Susan },{Correct Answer Nr.3 : b.) She doesn’t say },.x.b,';
var output = string.replace(/^[^{]+|[^}]+$/g, "");
console.log(output);
这里使用的正则表达式模式表示匹配：
^从字符串的开头[^{]+匹配一个或多个不是{的前导字符|或[^}]+匹配一个或多个不是}的尾随字符$在字符串的结尾
英文:
We can try the following regex replacement:
<!-- begin snippet: js hide: false console: true babel: false -->
<!-- language: lang-js -->
var string = '.,.a,,{Correct Answer Nr.1 : b.) Susan },{Correct Answer Nr.3 : b.) She doesn’t say },.x.b,';
var output = string.replace(/^[^{]+|[^}]+$/g, "");
console.log(output);
<!-- end snippet -->
The regex pattern used here says to match:
^from the start of the string[^{]+match one or more leading characters which are not{|OR[^}]+match one or more trailing characters which are not}$at the end of the string
答案2
得分: 0
匹配的结果是：
{正确答案1：b。）Susan },{正确答案3：b。）她没有说}
英文:
By greedy behaviour, pattern
{.*}
matches
{Correct Answer Nr.1 : b.) Susan },{Correct Answer Nr.3 : b.) She doesn’t say }
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