英文:
It is possible to dump content of a text file into a Python list?
问题
我有一个包含50个txt文件的目录。我想将每个文件的内容合并到一个Python列表中。
每个文件的内容如下：
line1
line2
line3
我正在使用以下代码将文件/文件路径放入一个列表中。我只需要循环遍历file_list并将每个txt文件的内容附加到列表中。
from pathlib import Path
def searching_all_files():
dirpath = Path(r'C:\num')
assert dirpath.is_dir()
file_list = []
for x in dirpath.iterdir():
if x.is_file():
file_list.append(x)
elif x is_dir():
file_list.extend(searching_all_files(x))
return file_list
但我不确定最佳方法。
也许循环类似于这个的内容？
注意：这不是真正的代码！只是从空中抓取的想法。问题不是如何修复这个问题。我只是展示这个作为一个思路。欢迎所有方法。
file_path = Path('.....')
with open(file_path) as f:
source_path = f.read().splitlines()
source_nospaces = [x.strip(' ') for x in source_path]
return source_nospaces
希望这对你有所帮助。
英文:
I have a directory of 50 txt files. I want to combine the contents of each file into a Python list.
Each file looks like;
line1
line2
line3
I am putting the files / file path into a list with this code. I just need to loop through file_list and append the content of each txt file to a list.
from pathlib import Path
def searching_all_files():
dirpath = Path(r'C:\num')
assert dirpath.is_dir()
file_list = []
for x in dirpath.iterdir():
if x.is_file():
file_list.append(x)
elif x.is_dir():
file_list.extend(searching_all_files(x))
return file_list
But I am unsure best method
Maybe loop something close to this?
NOTE: NOT REAL CODE!!!! JUST A THOUGHT PULLED FROM THE AIR. THE QUESTION ISNT HOW TO FIX THIS. I AM JUST SHOWING THIS AS A THOUGHT. ALL METHODS WELCOME.
file_path = Path(r'.....')
with open(file_path) as f:
source_path = f.read().splitlines()
source_nospaces = [x.strip(' ') for x in source_path]
return source_nospaces
答案1
得分: 3
你可以利用pathlib.rglob来递归搜索目录中的所有文件，并使用readlines()将内容追加到列表中：
from pathlib import Path
files = Path('/tmp/text').rglob('*.txt')
res = []
for file in files:
res += open(file).readlines()
print(res)
输出：
['file_content2\n', 'file_content3\n', 'file_content1\n']
英文:
You could make use of pathlib.rglob in order to search for all files in a directory recursively and readlines() to append the contents to list:
from pathlib import Path
files = Path('/tmp/text').rglob('*.txt')
res = []
for file in files:
res += open(file).readlines()
print(res)
Out:
['file_content2\n', 'file_content3\n', 'file_content1\n']
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