英文:
The array A(10) is given. Replace all the elements standing between the largest and the smallest with the number 100
问题
我有一个关于Python任务的问题
例如：
数组 [1, 5, 2, 3, -1, 3]
新数组 [1, 5, 100, 100, -1, 3]
我不知道如何做这个，因为我是Python新手。
英文:
I have a problem with python task
for example:
array [1, 5, 2, 3, -1, 3]
new_array [1, 5, 100, 100, -1, 3]
i dont know how do this cuz i new in python
答案1
得分: 0
你可以找到最小和最大值的索引，然后将对应的列表替换为100：
A = [1, 5, 2, 3, -1, 3]
start, end = sorted(map(A.index, (min(A), max(A)))
A[start+1:end] = [100] * len(A[start+1:end])
print(A) # [1, 5, 100, 100, -1, 3]
如果你需要它在一个单独的变量中，你可以事先复制（例如：new_array = array.copy()）并在复制上操作
英文:
You could find the indexes of the minimum and maximum values and then assign a corresponding list of 100s to the subscript:
A = [1, 5, 2, 3, -1, 3]
start,end = sorted(map(A.index,(min(A),max(A))))
A[start+1:end] = [100]*len(A[start+1:end])
print(A) # [1, 5, 100, 100, -1, 3]
If you need it to be in a separate variable you can make copy beforehand (ex: new_array = array.copy()) and work on the copy
答案2
得分: -1
我的解决方案仅适用于在最小值之前出现最大值的情况，但您可以轻松更新这个解决方案。
array = [1, 5, 2, 3, -1, 3]
c = []
for i, j in enumerate(array):
if i <= array.index(max(array)) or i >= array.index(min(array)):
c.append(j)
else:
c.append(100)
print(c)
英文:
my solution works only for this case when maximal value before minimal but you could easily update this solution.
array = [1, 5, 2, 3, -1, 3]
c = []
for i,j in enumerate(array):
if i<=(array.index(max(array))) or i>=array.index(min(array)):
c.append(j)
else:
c.append(100)
print(c)
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