Check if numeral within bounds in one statement

Is there a way to check if a number x is greater than a number a and less than a number b, without specifying x twice?

I can do this:

x = 4
a = 1
b = 10
x > a && x < b

...but is there a way to do something like this:

# not valid ruby, is there another way?
a < x < b

This does not answer the question exactly, please read the Edit part of the answer.

Tested this to work for x being an Integer and a Float.

(a..b).include? x

Edit:
As @spickermann pointed out in comments the original question excludes the beginning and the end of the interval.

To exclude the end is easy, this is what ... is for. Therefore

(a...b).include? x  # is the same as `a <= x && x < b`

To exclude the start of the interval is not that easy. One could use next_float:

(a.to_f.next_float...b).include? x

However even the (a...b) is something I would not use because it is not so common literal and in my opinion decreases readability of the code. With a.to_f.next_float we are making some really awkward code that may work for Integers and Floats but I would be afraid of other Numeric data types.

Unless someone brings completely different approach I would stick with x > a && x < b