打开二极管一段时间，以及在Arduino中执行下一个程序。

huangapple
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英文:

Switching on the diode for some time, as well as execution of the next program in Arduino

问题

在tinkercad中制作的电路
我使用继电器，因为我只有4根导线连接到LED二极管和这两个开关。

  1. int led = 12; // 红色LED
  2. int s1 = 9; // 开关1
  3. int s2 = 10; // 开关2
  4. int k1 = 3; // 第一个蓝色LED
  5. int k2 = 2; // 第二个蓝色LED
  6. int y1 = 11; // 继电器
  7. unsigned long startTime1 = 0;
  8. unsigned long startTime2 = 0;
  9. const int led1Duration = 6000; // 第一个蓝色LED持续时间
  10. const int led2Duration = 12000; // 第二个蓝色LED持续时间
  12. void setup()
  13. {
  14.   pinMode(led, OUTPUT);
  15.   pinMode(k1, OUTPUT);
  16.   pinMode(k2, OUTPUT);
  17.   pinMode(y1, OUTPUT);
  18.   pinMode(s1, INPUT);
  19.   pinMode(s2, INPUT);
  20. }
  22. void loop()
  23. {
  24.   if (digitalRead(s1) == HIGH && digitalRead(s2) == LOW)
  25.   {	
  26.     digitalWrite(k1, HIGH);
  27.     digitalWrite(y1, HIGH);
  28.     startTime1 = millis(); 
  29.   }
  30.   else
  31.   {
  32.     digitalWrite(led, LOW);
  33.   }
  34.   
  35.   if (digitalRead(s2) == HIGH && digitalRead(s1) == LOW)
  36.   {
  37.     digitalWrite(k2, HIGH);
  38.     digitalWrite(y1, HIGH);
  39.     startTime2 = millis(); 
  40.   }
  41.   else
  42.   {
  43.     digitalWrite(led, LOW);
  44.   }
  45.   
  46.   if (digitalRead(k1) == HIGH && (millis() - startTime1 >= led1Duration)) 
  47.   {
  48.     digitalWrite(k1, LOW);
  49.     digitalWrite(y1, LOW);
  50.   }
  51.   if (digitalRead(k2) == HIGH && (millis() - startTime2 >= led2Duration)) 
  52.   {
  53.     digitalWrite(k2, LOW);
  54.     digitalWrite(y1, LOW);
  55.   }
  56.   
  57.   if (digitalRead(k1) == HIGH && digitalRead(k2) == LOW)
  58.   {
  59.     digitalWrite(led, HIGH);
  60.     delay(200);
  61.     digitalWrite(led, LOW);
  62.     delay(200);
  63.   }
  64.   if (digitalRead(k2) == HIGH && digitalRead(k1) == LOW)
  65.   {
  66.     digitalWrite(led, HIGH);
  67.     delay(500);
  68.     digitalWrite(led, LOW);
  69.     delay(500);
  70.   }
  71.   if (digitalRead(k2) == HIGH && digitalRead(k1) == HIGH)
  72.   {
  73.     digitalWrite(led, HIGH);
  74.   }
  75. }

是否有更简单的方法来做到这一点，因为当我组装它时，开关的响应非常慢，蓝色LED会在一段时间后才会亮起。接下来，我使用了ESP8266，但是3V的继电器无法工作。我该如何使其正常工作？

英文:

The circuit made in tinkercad
I use the relay, because I have only 4 wires to led diode and this two switches.

  1. int led = 12; // red led
  2. int s1 = 9; //switch 1
  3. int s2 = 10; //switch 1
  4. int k1 = 3; // first blue led
  5. int k2 = 2; // second blue led
  6. int y1 = 11; // relay
  7. unsigned long startTime1 = 0;
  8. unsigned long startTime2 = 0;
  9. const int led1Duration = 6000; // first blue led time
  10. const int led2Duration = 12000; // second blue led time
  11. void setup()
  12. {
  13. pinMode(led, OUTPUT);
  14. pinMode(k1, OUTPUT);
  15. pinMode(k2, OUTPUT);
  16. pinMode(y1, OUTPUT);
  17. pinMode(s1, INPUT);
  18. pinMode(s2, INPUT);
  19. }
  20. void loop()
  21. {
  22. if (digitalRead(s1) == HIGH and digitalRead(s2) == LOW)
  23. {	
  24. digitalWrite(k1, HIGH);
  25. digitalWrite(y1, HIGH);
  26. startTime1 = millis(); 
  27. }
  28. else
  29. {
  30. digitalWrite(led, LOW);
  31. }
  32. if (digitalRead(s2) == HIGH and digitalRead(s1) == LOW)
  33. {
  34. digitalWrite(k2, HIGH);
  35. digitalWrite(y1, HIGH);
  36. startTime2 = millis(); 
  37. }
  38. else
  39. {
  40. digitalWrite(led, LOW);
  41. }
  42. if (digitalRead(k1) == HIGH && (millis() - startTime1 >= led1Duration)) 
  43. {
  44. digitalWrite(k1, LOW);
  45. digitalWrite(y1, LOW);
  46. }
  47. if (digitalRead(k2) == HIGH && (millis() - startTime2 >= led2Duration)) 
  48. {
  49. digitalWrite(k2, LOW);
  50. digitalWrite(y1, LOW);
  51. }
  52. if (digitalRead(k1) == HIGH and digitalRead(k2) == LOW)
  53. {
  54. digitalWrite(led, HIGH);
  55. delay(200);
  56. digitalWrite(led, LOW);
  57. delay(200);
  58. }
  59. if (digitalRead(k2) == HIGH and digitalRead(k1) == LOW)
  60. {
  61. digitalWrite(led, HIGH);
  62. delay(500);
  63. digitalWrite(led, LOW);
  64. delay(500);
  65. }
  66. if (digitalRead(k2) == HIGH and digitalRead(k1) == HIGH)
  67. {
  68. digitalWrite(led, HIGH);
  69. }
  70. }

Is there easier way to do that, cause when I assembled it the switches work very slow that blue led turn on after some time. Next I use the esp2866 but the relay for 3V doesn't turn on. How can I make it to work?

答案1

得分: 0

  1. @Peter 是真的：避免阻塞延迟代码。
  3. 这里有一个例子：我稍微简化了你的代码，并添加了else if以使其更可读。
  5. 更新1：
  7.     int led = 12; // 红色LED
  8.     int s1 = 9; // 开关1
  9.     int s2 = 10; // 开关2
  10.     int k1 = 3; // 第一个蓝色LED
  11.     int k2 = 2; // 第二个蓝色LED
  12.     int y1 = 11; // 继电器
  13.     unsigned long startTime1 = 0;
  14.     unsigned long startTime2 = 0;
  15.     unsigned long t200 = 200;
  16.     unsigned long t500 = 500;
  17.     const int led1Duration = 6000; // 第一个蓝色LED亮起时间
  18.     const int led2Duration = 12000; // 第二个蓝色LED亮起时间
  20. void setup()
  21. {
  22.   pinMode(led, OUTPUT);
  23.   pinMode(k1, OUTPUT);
  24.   pinMode(k2, OUTPUT);
  25.   pinMode(y1, OUTPUT);
  26.   pinMode(s1, INPUT);
  27.   pinMode(s2, INPUT);
  28. }
  30. void loop()
  31. {
  32.   if (digitalRead(s1) && !digitalRead(s2)) {
  33.     digitalWrite(k1, HIGH);
  34.     digitalWrite(y1, HIGH);
  35.     startTime1 = millis();
  36.     blinkLed200();
  37.   } else if (!digitalRead(s1) && digitalRead(s2)) {
  38.     digitalWrite(k2, HIGH);
  39.     digitalWrite(y1, HIGH);
  40.     startTime2 = millis();
  41.     blinkLed500();
  42.   }
  44.   if (digitalRead(k1) && (millis() - startTime1 >= led1Duration)) {
  45.     digitalWrite(k1, LOW);
  46.     digitalWrite(y1, LOW);
  47.     digitalWrite(led, LOW);
  48.   }
  50.   if (digitalRead(k2) && (millis() - startTime2 >= led2Duration)) {
  51.     digitalWrite(k2, LOW);
  52.     digitalWrite(y1, LOW);
  53.     digitalWrite(led, LOW);
  54.   }
  55. }
  57. void blinkLed200() {
  58.   if (millis() - t200 > 200) { //每200毫秒闪烁一次
  59.     t200 = millis();
  60.     digitalWrite(led, !digitalRead(led));
  61.   }
  62. }
  64. void blinkLed500() {
  65.   if (millis() - t500 > 500) { //每500毫秒闪烁一次
  66.     t500 = millis();
  67.     digitalWrite(led, !digitalRead(led));
  68.   }
  69. }
  71. 这些3V继电器的电阻非常低，我不确定数字输出是否足够强大。个人建议通过晶体管来控制继电器。
英文:

@Peter is true : avoid blocking delay code.

here is an example : I have a little simplified your code and added else if to make it more readable.

update1 :

  1.    int led = 12; // red led
  2. int s1 = 9; //switch 1
  3. int s2 = 10; //switch 1
  4. int k1 = 3; // first blue led
  5. int k2 = 2; // second blue led
  6. int y1 = 11; // relay
  7. unsigned long startTime1 = 0;
  8. unsigned long startTime2 = 0;
  9. unsigned long t200 = 200;
  10. unsigned long t500 = 500;
  11. const int led1Duration = 6000; // first blue led time
  12. const int led2Duration = 12000; // second blue led time
  13. void setup()
  14. {
  15. pinMode(led, OUTPUT);
  16. pinMode(k1, OUTPUT);
  17. pinMode(k2, OUTPUT);
  18. pinMode(y1, OUTPUT);
  19. pinMode(s1, INPUT);
  20. pinMode(s2, INPUT);
  21. }
  22. void loop()
  23. {
  24. if (digitalRead(s1) && !digitalRead(s2)) {
  25. digitalWrite(k1, HIGH);
  26. digitalWrite(y1, HIGH);
  27. startTime1 = millis();
  28. blinkLed200();
  29. } else if (!digitalRead(s1) && digitalRead(s2)) {
  30. digitalWrite(k2, HIGH);
  31. digitalWrite(y1, HIGH);
  32. startTime2 = millis();
  33. blinkLed500();
  34. }
  35. if (digitalRead(k1) && (millis() - startTime1 >= led1Duration)) {
  36. digitalWrite(k1, LOW);
  37. digitalWrite(y1, LOW);
  38. digitalWrite(led, LOW);
  39. }
  40. if (digitalRead(k2) && (millis() - startTime2 >= led2Duration)) {
  41. digitalWrite(k2, LOW);
  42. digitalWrite(y1, LOW);
  43. digitalWrite(led, LOW);
  44. }
  45. }
  46. void blinkLed200() {
  47. if (millis() - t200 > 200) { //tick every 200mS
  48. t200 = millis();
  49. digitalWrite(led, !digitalRead(led));
  50. }
  51. }
  52. void blinkLed500() {
  53. if (millis() - t500 > 500) { //tick every 500mS
  54. t500 = millis();
  55. digitalWrite(led, !digitalRead(led));
  56. }
  57. }

The 3V relays have a very low resistance and I am not sure that the digital outputs are powerful enough. Personally I always switch relays via a transistor.

huangapple
  • 本文由 发表于 2023年2月18日 00:44:20
  • 转载请务必保留本文链接：https://go.coder-hub.com/75487038.html
  • arduino
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