The code that I have tried is not displaying the expected output. How can I rectify my code which is related to patterns?

I need to print a square pattern where the number increases as per the row, for example consider variable 'i' which represents row value, if you initialize i=1 and increase the value till 'n' which is user input using while loop, the first row will print 1, second row will print 2 and so on till it reaches the value 'n'. Additionally I created variable for column and named it 'j' whose value also increases till it reaches n.

The output that I'm getting though is:
enter image description here
The code that I have written is: (java)
enter image description here

Scanner s = new Scanner(System.in);
        int n = s.nextInt();
        int i =1;
        while(i<=n){
            int j = 1;
            while(j<=n){
                System.out.println(i);
                j=j+1;
            }
            System.out.println();
            i=i+1;
        }

Why is the output for the above code:
enter image description here instead of

• 1111
• 2222
• 3333
• 4444

Please help me out.

Problem

The doc states the following and you know it

> Prints an integer and then terminates the line

Fix

Use print instead

while (i <= n) {
    int j = 1;
    while (j <= n) {
        System.out.print(i);
        ++j;
    }
    System.out.println();
    ++i;
}

Improvements

Could be a little bit nicer with for loops

for (int i = 1; i <= n; ++i) {
    for (int j = 1; j <= n; ++j) {
        System.out.print(i);
    }
    System.out.println();
}

Using String.repeat

for (int i = 1; i <= n; ++i) {
    System.out.println(Integer.toString(i).repeat(n));
}