英文:
How to convert datetime.time to datetime.datetime?
问题
Error TypeError: unsupported operand type(s) for -: 'datetime.time' and 'datetime.time'
我正在尝试减去两个时间，它们都是以datetime.time格式。如何在Python中将它们转换为datetime.datetime。
我有一个问题，需要一个解决方法来编写我的代码。
英文:
I am trying to subtract 2 times and they both are in datetime.time format. How to convert them to datetime.datetime in python.
> Error TypeError: unsupported operand type(s) for -: 'datetime.time' and 'datetime.time'
I have a question to which I need a workaround to write my code.
答案1
得分: 0
import datetime
time1 = datetime.time(1, 0, 0)
time2 = datetime.time(1, 30, 0)
today = datetime.date.today()
datetime1 = datetime.datetime.combine(today, time1)
datetime2 = datetime.datetime.combine(today, time2)
time_diff = datetime2 - datetime1
# 结果是一个 timedelta 对象
print(time_diff)
英文:
import datetime
time1 = datetime.time(1, 0, 0)
time2 = datetime.time(1, 30, 0)
today = datetime.date.today()
datetime1 = datetime.datetime.combine(today, time1)
datetime2 = datetime.datetime.combine(today, time2)
time_diff = datetime2 - datetime1
# The result is a timedelta object
print(time_diff)
You may use a common datetime, here today, and then subtract them
答案2
得分: 0
你可以使用datetime.combine()函数，但是要注意，这种方法存在潜在的问题。
import datetime
t1 = datetime.time(8) # 上午8点
t2 = datetime.time(17) # 下午5点
d = datetime.date(2000, 1, 1) # 任意日期
delta = datetime.datetime.combine(d, t2) - datetime.datetime.combine(d, t1)
print(delta)
打印结果：
<pre>
datetime.timedelta(seconds=32400)
</pre>
潜在的问题：
-
不考虑夏令时
-
1点减去11点晚上得到的是负22小时，这可能不是你想要的
-
请注意，如果
time对象中包含tzinfo，它将被继承到datetime对象中，这可能是你想要的，也可能不是。
英文:
You can use the datetime.combine() function BUT!! be aware that there are potential pitfalls to this approach.
import datetime
t1 = datetime.time(8) # 8:00 AM
t2 = datetime.time(17) # 5:00 PM
d = datetime.date(2000, 1, 1) # Arbitrary date
delta = datetime.datetime.combine(d, t2) - datetime.datetime.combine(d, t1)
print(delta)
Prints:
<pre>
datetime.timedelta(seconds=32400)
</pre>
Potential pitfalls:
-
Does not account for daylight savings
-
1AM minus 11PM is negative 22 hours, that may not be what you want
-
Note that if the
tzinfois present in thetimeobject, it will be inherited by thedatetimeobject—this may or may not be what you want
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