英文:
Qt - QTest::keyClick() - is it synchronized to paint?
问题
我有一个GUI，我想要使用QTest进行测试。
我计划创建一个单独的线程，执行QTest::keyClick()测试步骤，但我想要将我的测试步骤与QWidget::repaint()同步，也就是说，我希望每个QTest::keyClick()都发生在前一个QTest::keyClick()引起的重绘之后（如果有的话）。
QTest::keyClick()- 来自步骤1的重绘
QTest::keyClick()- 来自步骤2的重绘
我不希望出现以下情况：
QTest::keyClick()QTest::keyClick()- 来自步骤1的重绘
- 来自步骤2的重绘
问题
如何确保keyClick()不会在上一个keyClick()的绘图事件之前发生？
英文:
I have a GUI which I want to test with QTest.
I'm planning on having a separate thread which executes QTest::keyClick() test steps but I want to synchronize my test steps with QWidget::repaint() i.e. I want each QTest::keyClick() to happen only after the repaint (if any) caused by the repaint from the previous QTest::keyClick()
QTest::keyClick()- Repaint from step 1
QTest::keyClick()- Repaint from step 2
I do not want
QTest::keyClick()QTest::keyClick()- Repaint from step 1
- Repaint from step 2
QUESTION
How to make sure keyClick()s do not occur before paint event from previous keyClick()?
答案1
得分: 0
不需要同步：每次调用 keyClick() 都会导致调用 qApp->processEvents()。
static void simulateEvent(QWindow *window, bool press, int code,
Qt::KeyboardModifiers modifier, QString text, bool repeat, int delay=-1)
{
QEvent::Type type;
type = press ? QEvent::KeyPress : QEvent::KeyRelease;
qt_handleKeyEvent(window, type, code, modifier, text, repeat, delay);
qApp->processEvents();
}
这将在下一个 QTest.keyClick() 之前触发任何绘图事件。
英文:
No need for synchronization: each call to keyClick() results in a call to qApp->processEvents()
static void simulateEvent(QWindow *window, bool press, int code,
Qt::KeyboardModifiers modifier, QString text, bool repeat, int delay=-1)
{
QEvent::Type type;
type = press ? QEvent::KeyPress : QEvent::KeyRelease;
qt_handleKeyEvent(window, type, code, modifier, text, repeat, delay);
qApp->processEvents();
}
which would trigger any paint events before the next QTest.keyClick().
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