禁用分页的第一个和最后一个按钮。

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英文:

Disable pagination First and Last buttons

问题

使用tabulator和分页功能时,我想禁用"第一页"和"最后一页"按钮。
我尝试使用paginationButtonCount属性,将其设置为3,而不是默认的5,但这没有改变任何东西。

是否有一种方法可以实现这一点?

此外,是否有一种方法可以自己设置分页按钮的启用/禁用?

英文:

When using tabulator and the pagination feature, I want to disable First and Last buttons.
I tried using the paginationButtonCount property, and set it to 3 instead of the default 5, but that didn't change anything.

Is there a way to accomplish that?

Also, is there a way to set the enablement/disablement of the pagination buttons on my own?

答案1

得分: 0

为了解决这个问题,我检查了默认分页HTML的外观。然后,我使用Tabulator的footerElement配置来准备自己的页脚元素:

footerElement: preparePaginatorElement()

结果的方法如下:

function preparePaginatorElement() {
    previousButton = document.createElement("button");
    previousButton.classList.add("tabulator-page");
    previousButton.type = "button";
    previousButton.role = "button";
    previousButton.ariaLabel = "Prev Page";
    previousButton.title = "Prev Page";
    previousButton.setAttribute("data-page", "prev");
    previousButton.disabled = true;
    previousButton.innerText = "Prev Page";
    previousButton.addEventListener("click", () => changePage(currentPage - 1, true));

    nextButton = document.createElement("button");
    nextButton.classList.add("tabulator-page");
    nextButton.type = "button";
    nextButton.role = "button";
    nextButton.ariaLabel = "Next Page";
    nextButton.title = "Next Page";
    nextButton.setAttribute("data-page", "next");
    nextButton.disabled = true;
    nextButton.innerText = "Next Page";
    nextButton.addEventListener("click", () => changePage(currentPage + 1, true));

    pageButton = document.createElement("button");
    pageButton.classList.add("tabulator-page");
    pageButton.type = "button";
    pageButton.role = "button";
    pageButton.innerText = "1";
    pageButton.style.cursor = "default";

    const pagesSpan = document.createElement("span");
    pagesSpan.classList.add("tabulator-pages");
    pagesSpan.appendChild(pageButton);

    const paginatorSpan = document.createElement("span");
    paginatorSpan.classList.add("tabulator-paginator");
    paginatorSpan.appendChild(previousButton);
    paginatorSpan.appendChild(pagesSpan);
    paginatorSpan.appendChild(nextButton);

    const footerContentsDiv = document.createElement("div");
    footerContentsDiv.classList.add("tabulator-footer-contents");
    footerContentsDiv.appendChild(paginatorSpan);

    const footerDiv = document.createElement("div");
    footerDiv.classList.add("tabulator-footer");
    footerDiv.appendChild(footerContentsDiv);

    return footerDiv;
}
英文:

For solving this, I inspected how the default pagination html looked like.
Then, I used tabulator's footerElement configuration in order to prepare my own footer element:

footerElement: preparePaginatorElement()

The resulting method looks like this:

function preparePaginatorElement() {
previousButton = document.createElement("button");
previousButton.classList.add("tabulator-page");
previousButton.type = "button";
previousButton.role = "button";
previousButton.ariaLabel = "Prev Page";
previousButton.title = "Prev Page";
previousButton.setAttribute("data-page", "prev");
previousButton.disabled = true;
previousButton.innerText = "Prev Page";
previousButton.addEventListener("click", () => changePage(currentPage - 1, true));
nextButton = document.createElement("button");
nextButton.classList.add("tabulator-page");
nextButton.type = "button";
nextButton.role = "button";
nextButton.ariaLabel = "Next Page";
nextButton.title = "Next Page";
nextButton.setAttribute("data-page", "next");
nextButton.disabled = true;
nextButton.innerText = "Next Page";
nextButton.addEventListener("click", () => changePage(currentPage + 1, true));
pageButton = document.createElement("button");
pageButton.classList.add("tabulator-page"/*, "active"*/);
pageButton.type = "button";
pageButton.role = "button";
pageButton.innerText = "1";
pageButton.style.cursor = "default";
const pagesSpan = document.createElement("span");
pagesSpan.classList.add("tabulator-pages");
pagesSpan.appendChild(pageButton);
const paginatorSpan = document.createElement("span");
paginatorSpan.classList.add("tabulator-paginator");
paginatorSpan.appendChild(previousButton);
paginatorSpan.appendChild(pagesSpan);
paginatorSpan.appendChild(nextButton);
const footerContentsDiv = document.createElement("div");
footerContentsDiv.classList.add("tabulator-footer-contents");
footerContentsDiv.appendChild(paginatorSpan);
const footerDiv = document.createElement("div");
footerDiv.classList.add("tabulator-footer");
footerDiv.appendChild(footerContentsDiv);
return footerDiv;
}

答案2

得分: 0

在使用远程分页的情况下,你可以在你的ajaxResponse函数中隐藏按钮。

ajaxResponse:function(url, params, response){
    document.querySelector('[title="Last Page"]').hidden = true;
    return response.data;
}
英文:

Assuming you're using remote pagination, you can hide the button in your ajaxResponse function.

ajaxResponse:function(url, params, response){
document.querySelector('[title="Last Page"]').hidden = true;
return response.data;

huangapple
  • 本文由 发表于 2023年2月16日 02:39:58
  • 转载请务必保留本文链接:https://go.coder-hub.com/75464141.html
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