英文:
get closest number out of array in array in javascript
问题
const myarr = [[12, 42], [12, 56], [30, 54]];console.log(colsest_out_of_closest(myarr, [12, 50]));
英文:
I know this is a bit on nonsense but I need to get the closest number out of 2 arrays or:
const myarr = [[12, 42], [12, 56], [30, 54]]console.log(colsest_out_of_closest(myarr, [12, 50]))</details># 答案1**得分**: 1这是您要翻译的代码部分：```javascriptconst closest_out_of_closest = (arr, criteria) => {const [min, max] = criteria;let result, prevDiff = Number.MAX_VALUE;arr.forEach((item) => {const [localMin, localMax] = item;const diff = Math.abs(localMin - min) + Math.abs(localMax - max);if (diff < prevDiff) {prevDiff = diff;result = item;}});return result;};const myarr = [[12, 42], [12, 56], [30, 54]];console.log(closest_out_of_closest(myarr, [12, 50])); // [12, 56]
const closestRange = (arr, [min, max]) =>arr.reduce((acc, [lMin, lMax]) =>(diff => diff < acc.prev ? { result: [lMin, lMax], prev: diff } : acc)(Math.abs(lMin - min) + Math.abs(lMax - max)),{ result: null, prev: Number.MAX_VALUE }).result;console.log(closestRange([[12, 42], [12, 56], [30, 54]], [12, 50])); // [12, 56]
我已经为您提供了翻译，不包括代码部分。
英文:
It looks like you want to find the smallest difference between both the min and the max.
<!-- begin snippet: js hide: false console: true babel: false -->
<!-- language: lang-js -->
const closest_out_of_closest = (arr, criteria) => {const [min, max] = criteria;let result, prevDiff = Number.MAX_VALUE;arr.forEach((item) => {const [localMin, localMax] = item;const diff = Math.abs(localMin - min) + Math.abs(localMax - max);if (diff < prevDiff) {prevDiff = diff;result = item;}});return result;};const myarr = [[12, 42], [12, 56], [30, 54]];console.log(closest_out_of_closest(myarr, [12, 50])); // [12, 56]
<!-- end snippet -->
Here is a reducer version that is less bytes, but still readable:
<!-- begin snippet: js hide: false console: true babel: false -->
<!-- language: lang-js -->
const closestRange = (arr, [min, max]) =>arr.reduce((acc, [lMin, lMax]) =>(diff => diff < acc.prev ? { result: [lMin, lMax], prev: diff } : acc)(Math.abs(lMin - min) + Math.abs(lMax - max)),{ result: null, prev: Number.MAX_VALUE }).result;console.log(closestRange([[12, 42], [12, 56], [30, 54]], [12, 50])); // [12, 56]
<!-- end snippet -->
答案2
得分: 1
以下是代码部分的内容，不做翻译：
You could check the absolute delta.
<!-- begin snippet: js hide: false console: true babel: false -->
<!-- language: lang-js -->
const
getClosest = (a, b, t) => Math.abs(t - a) < Math.abs(t - b) ? a : b,
getClosestPair = (target, array) => values.reduce((a, b) =>
[0, 1].map(i => getClosest(a[i], b[i], target[i]))
),
values = [[12, 42], [12, 56], [30, 54]],
closest = getClosestPair([12, 50], values);
console.log(closest);
<!-- end snippet -->
英文:
You could check the absolute delta.
<!-- begin snippet: js hide: false console: true babel: false -->
<!-- language: lang-js -->
const
getClosest = (a, b, t) => Math.abs(t - a) < Math.abs(t - b) ? a : b,
getClosestPair = (target, array) => values.reduce((a, b) =>
[0, 1].map(i => getClosest(a[i], b[i], target[i]))
),
values = [[12, 42], [12, 56], [30, 54]],
closest = getClosestPair([12, 50], values);
console.log(closest);
<!-- end snippet -->
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