英文:
Drop duplicate rows from DataFrame based on conditions on multiple columns
问题
以下是翻译好的部分：
我有如下的数据框：| id | value | date || --- | ------|------------------ || 001 | True |01/01/2022 00:00:00|| 002 | False |03/01/2022 00:00:00|| 003 | True |03/01/2022 00:00:00|| 001 | False |01/01/2022 01:30:00|| 001 | True |01/01/2022 01:30:00|| 002 | True |03/01/2022 00:00:00|| 003 | True |03/01/2022 00:30:00|| 004 | False |03/01/2022 00:30:00|| 005 | False |01/01/2022 00:00:00|在原始数据框中有一些重复的行，我想根据以下条件删除重复的行：- 如果在**相同日期和相同时间存在重复的id**，则选择值为"True"的行（例如，id = 002）- 如果存在**相同值的重复id**，则选择具有最新日期和时间的行（例如，id = 003）- 如果存在**重复的id**，则选择具有最新日期和时间并且值为"True"的行（例如，id = 001）预期的输出是：| id | value | date || --- | ------|------------------ || 001 | True |01/01/2022 01:30:00|| 002 | True |03/01/2022 00:00:00|| 003 | True |03/01/2022 00:30:00|| 004 | False |03/01/2022 00:30:00|| 005 | False |01/01/2022 00:00:00|有人可以建议我如何根据上述条件从数据框中删除重复项吗？谢谢。
希望这能帮助你。
英文:
I have dataframe as follow:
| id | value | date |
|---|---|---|
| 001 | True | 01/01/2022 00:00:00 |
| 002 | False | 03/01/2022 00:00:00 |
| 003 | True | 03/01/2022 00:00:00 |
| 001 | False | 01/01/2022 01:30:00 |
| 001 | True | 01/01/2022 01:30:00 |
| 002 | True | 03/01/2022 00:00:00 |
| 003 | True | 03/01/2022 00:30:00 |
| 004 | False | 03/01/2022 00:30:00 |
| 005 | False | 01/01/2022 00:00:00 |
There are some duplicate rows in the raw dataframe and I would like to remove duplicate rows based on following conditions:
- If there are duplicate ids on the same date and same time, select a row with value "True" (e.g., id = 002)
- If there are duplicate ids with same value, select a row with the latest date and time (e.g., id == 003)
- If there are duplicate ids, select row with the latest date and time and select a row with value "True" (e.g., id == 001)
Expected output:
| id | value | date |
|---|---|---|
| 001 | True | 01/01/2022 01:30:00 |
| 002 | True | 03/01/2022 00:00:00 |
| 003 | True | 03/01/2022 00:30:00 |
| 004 | False | 03/01/2022 00:30:00 |
| 005 | False | 01/01/2022 00:00:00 |
Can somebody suggested me how to drop duplicates from dataframe based on above mentioned conditions ?
Thanks.
答案1
得分: 1
output = (
df.sort_values(by=['date', 'value'], ascending=False)
.drop_duplicates(subset='id')
.sort_values(by='id')
)
print(output)
Output
id value date4 1 True 2022-01-01 01:30:005 2 True 2022-03-01 00:00:006 3 True 2022-03-01 00:30:007 4 False 2022-03-01 00:30:008 5 False 2022-01-01 00:00:00
英文:
It looks like perhaps you just need to sort your dataframe prior to dropping duplicates. Something like this:
output = (df.sort_values(by=['date','value'], ascending=False).drop_duplicates(subset='id').sort_values(by='id'))
print(output)
Output
id value date4 1 True 2022-01-01 01:30:005 2 True 2022-03-01 00:00:006 3 True 2022-03-01 00:30:007 4 False 2022-03-01 00:30:008 5 False 2022-01-01 00:00:00
通过集体智慧和协作来改善编程学习和解决问题的方式。致力于成为全球开发者共同参与的知识库，让每个人都能够通过互相帮助和分享经验来进步。
评论