英文:
How to parse json file
问题
我在解析中遇到了问题
我的 JSON 文件：
[{"username": "abc","number": "1","Coordinates": "3479087.7179635554,4723293.992024612,3587934.046241646,4936094.678770542"},{"username": "ab","number": "2","Coordinates": "3638076.736796722,4693942.173163104,3669874.540563355,4955662.558011548"}]
模型：
namespace WebUygAPI.Models{public class DrawInfo{public string username { get; set; }public string number { get; set; }public string coordinates { get; set; }}}
我在控制器中遇到的问题是：
[HttpGet][Route("GetDraws")]public async Task<IActionResult> get(){string filePath = @"C:\Users\Casper\source\repos\WebUygAPI\WebUygAPI\LineData.json";using (StreamReader file = new StreamReader(filePath)){string o1 = file.ReadToEnd();}return Ok();}
当我进行调试时，我可以看到 o1 中的 JSON 文件，但我无法解析它。
我尝试进行解析，但出现了错误，例如
newtonsoft.json.jsonreaderexception: 在解析值时遇到意外字符
英文:
I have a problem with parsing
my json file:
[{"username": "abc","number": "1","Coordinates": "3479087.7179635554,4723293.992024612,3587934.046241646,4936094.678770542"},{"username": "ab","number": "2","Coordinates": "3638076.736796722,4693942.173163104,3669874.540563355,4955662.558011548"}]
modal:
namespace WebUygAPI.Models{public class DrawInfo{public string username { get; set; }public string number { get; set; }public string coordinates { get; set; }}}
The problem I'm having in the controller is:
[HttpGet][Route("GetDraws")]public async Task<IActionResult> get(){string filePath = @"C:\Users\Casper\source\repos\WebUygAPI\WebUygAPI\LineData.json";using (StreamReader file = new StreamReader(filePath)){string o1 = file.ReadToEnd();}return Ok();}
When I'm debugging I can see json file in o1 but I couldn't parse it.
I tried to parse but I had errors such as
> newtonsoft.json.jsonreaderexception: unexpected character encountered while parsing value
答案1
得分: -1
我建议使用这段代码：
使用 Newtonsoft.Json;var json = File.ReadAllText(filePath);List<DrawInfo> info = JsonConvert.DeserializeObject<List<DrawInfo>>(json);
英文:
I recommend this code
using Newtonsoft.Json;var json = File.ReadAllText(filePath);List<DrawInfo> info = JsonConvert.DeserializeObject<List<DrawInfo>>(json);</details>
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