Typescript按字符串属性值排序

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英文:

Typescript sort by string property value

问题

我有一个对象列表,我想按字符串属性进行排序。属性值是D1, D2 ... D10 ... DXX。它始终是D后面跟着数字。当我使用以下代码按属性排序数组时,它没有按我期望的方式升序排序。我正在使用以下代码来对数组进行排序。

this.list = v.sort((a, b) => a.property.localeCompare(b.property));

结果按如下方式排序:

索引 属性值
0 D10
1 D11
2 D3
3 D5
... ...

我如何实现正确的排序?示例:

索引 属性值
0 D3
1 D5
2 D10
3 D11
... ...
英文:

I have a list of object I want to sort by string property. Property values are D1, D2 ... D10 ... DXX. It's always D with number. When I use this code to sort the array by property, it doesn't sort it the way I expect to - ascending. I am using this piece of code to sort array.

this.list = v.sort((a, b) => a.property.localeCompare(b.property));

Result are sorted like this:

Index Property value
0 D10
1 D11
2 D3
3 D5
... ...

How do I achieve sorting it the right way? Example:

Index Property value
0 D3
1 D5
2 D10
3 D11
... ...

答案1

得分: 2

您的属性是字符串,因此它们按字典顺序排序。

我认为您想要按字符串值的"数值组件"进行排序。因此,您需要从字符串中提取数字以执行数值排序。

extractNumber(stringValue: string) {
  // 假定所有字符串都以单个字符 'D' 为前缀
  return Number(stringValue.slice(1))
}

this.list = v.sort((a, b) => extractNumber(a.property) - extractNumber(b.property));

参考链接

英文:

Your properties are strings, therefore they are sorted lexicographically

What I believe you want is to sort by the "numeric component of your string value". You therefore have to extract the number from the string to perform a numeric sort

extractNumber(stringValue: string) {
  // Assumes all strings have a single character 'D' prepended
  return Number(stringValue.slice(1))
}

this.list = v.sort((a, b) => extractNumber(a.property) - extractNumber(b.property));

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  • 本文由 发表于 2023年2月14日 21:05:26
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