英文:
Return several values inside for loop
问题
我有一个必须使用for循环返回多个值的函数。我不希望将这些值存储在列表或字典中。由于使用return，我只得到第一个值。如何连续返回所有值？我尝试使用生成器和yield，但不确定如何使用它。
以下是该函数：
import randomdef my_function():for i in range(3):return(dict(x=[[random.randint(0,10)]], y=[[random.randint(0,10)]]), 0)
生成器和使用yield适用于我的需求吗？
英文:
I have a function that must return several values using a for loop. I do not wish to store the values inside a list or a dict. Because of the use of the return, I only get the first value. How can I return all values successively? I tried using generators and yield but I'm not sure how to use it.
here is the function:
import randomdef my_function():for i in range(3):return(dict(x=[[random.randint(0,10)]], y=[[random.randint(0,10)]]), 0)
Are generators and the use of yield suited for my need?
答案1
得分: 1
将`return`替换为`yield`以创建一个生成器：```pythonimport randomdef my_function():for i in range(3):yield dict(x=[[random.randint(0,10)]], y=[[random.randint(0,10)]]), 0g = my_function()for d in g:print(d)
输出：
({'x': [[0]], 'y': [[10]]}, 0)({'x': [[0]], 'y': [[1]]}, 0)({'x': [[3]], 'y': [[0]]}, 0)
您还可以使用next手动消耗下一个值：
g = my_function()print(next(g))print(next(g))print(next(g))print(next(g)) # 会引发 StopIteration 异常
输出：
({'x': [[4]], 'y': [[4]]}, 0)({'x': [[4]], 'y': [[9]]}, 0)({'x': [[7]], 'y': [[2]]}, 0)...StopIteration:
英文:
Replace return by yield to create a generator:
import randomdef my_function():for i in range(3):yield dict(x=[[random.randint(0,10)]], y=[[random.randint(0,10)]]), 0g = my_function()for d in g:print(d)
Output:
({'x': [[0]], 'y': [[10]]}, 0)({'x': [[0]], 'y': [[1]]}, 0)({'x': [[3]], 'y': [[0]]}, 0)
You can also use next to consume manually the next value:
g = my_function()print(next(g))print(next(g))print(next(g))print(next(g)) # Will raise a StopIteration exception
Output:
({'x': [[4]], 'y': [[4]]}, 0)({'x': [[4]], 'y': [[9]]}, 0)({'x': [[7]], 'y': [[2]]}, 0)...StopIteration:
答案2
得分: 1
我希望这能让你更好地理解。接下来，逐个为你提供值，如果你想获取所有的值，请将你的函数包装在一个列表内。import randomdef my_function():for i in range(3):yield(dict(x=[[random.randint(0,10)]], y=[[random.randint(0,10)]]), 0)a = my_function()print(next(a)) # 逐个获取print(next(a))print(list(my_function())) # 获取所有值
英文:
I hope, this gives you better understanding. next gives you value one by one and if you want all values wrap your function inside a list
import randomdef my_function():for i in range(3):yield(dict(x=[[random.randint(0,10)]], y=[[random.randint(0,10)]]), 0)a = my_function()print(next(a)) # one by oneprint(next(a))print(list(my_function())) # get all values
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