问题

Java

String hash = "806abe48226985c5fb0e878792232204d74643e190e25a4c20a97748d52b191c";
BigInteger bigInt = new BigInteger(hash, 16);
System.out.println(bigInt.mod(BigInteger.valueOf(11)).intValue());

Result:
4

<details>
<summary>英文:</summary>

The code below in JS converts a Hash to a number, but I tried to write a similar code in Java and both return different results.

What&#39;s the best way to get the same result shown in JS using Java?

**JS**

const hash = "806abe48226985c5fb0e878792232204d74643e190e25a4c20a97748d52b191c"
console.log(parseInt(hash, 16) % 11);

**Result:**
2


**Java**

String hash = "806abe48226985c5fb0e878792232204d74643e190e25a4c20a97748d52b191c";
BigInteger bigInt = new BigInteger(hash, 16);
System.out.println(bigInt.mod(BigInteger.valueOf(11)).intValue());

**Result:**
4


</details>


# 答案1
**得分**: 3

正确的值是 `4`。JavaScript 片段的结果是不正确的，因为数字太大无法准确表示。请使用 `BigInt` 替代。

<details>
<summary>英文:</summary>

The correct value is `4`. The result from the JavaScript snippet is incorrect, as the number is too large to be represented accurately. Use `BigInt` instead.

&lt;!-- begin snippet: js hide: false console: true babel: false --&gt;

&lt;!-- language: lang-js --&gt;

    const hash = &quot;806abe48226985c5fb0e878792232204d74643e190e25a4c20a97748d52b191c&quot;
    console.log(Number.isSafeInteger(parseInt(hash, 16))); // do not use this!
    console.log((BigInt(&#39;0x&#39; + hash) % 11n).toString());

&lt;!-- end snippet --&gt;



</details>