使用Newtonsoft JSON反序列化包含数组/列表的对象，使用字典。

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英文:

using newtonsoft json deserialize object that contains array/list using dictionary

问题

我想将 JSON 转换为对象。下面的代码有效。

  1. internal class Program
  2. {
  3.     static void Main(string[] args)
  4.     {
  5.         string json = @"{
  6.                   'name': 'Ayrton Senna',
  7.                   'friends': [
  8.                     {
  9.                       'name': 'John',
  10.                       'age': 34
  11.                     },
  12.                     {
  13.                       'name': 'Jack',
  14.                       'age': 32
  15.                     }
  16.                   ]
  17.                 }";
  19.         var person = JsonConvert.DeserializeObject<Person>(json);
  20.     }
  22.     public class Person
  23.     {
  24.         public string Name { get; set; }
  25.         public List<Friend> Friends { get; set; }
  27.         public class Friend
  28.         {
  29.             public string Name { get; set; }
  30.             public int Age { get; set; }
  31.         }
  32.     }
  33. }

然而，在 Person 类中，我希望属性 List<Friend> 变成字典。键将是字符串，应该从 JSON 中获取而不是硬编码。值将是对象列表。

示例：

  1. public class Person
  2. {
  3.     public string Name { get; set; }
  4.     public Dictionary<string, List<Friend>> Friends { get; set; }
  6.     public class Friend
  7.     {
  8.         public string Name { get; set; }
  9.         public int Age { get; set; }
  10.     }
  11. }

我之所以这样做是因为当我有不同的 JSON 时，例如：

  1. {
  2.   "id": 1,
  3.   "name": "Ayrton Senna",
  4.   "mates": [
  5.     {
  6.       "name": "John",
  7.       "age": 12
  8.     },
  9.     {
  10.       "name": "Jack",
  11.       "age": 32
  12.     }
  13.   ]
  14. }

另一个示例的 JSON：

  1. {
  2.   "id": 1,
  3.   "name": "Ayrton Senna",
  4.   "companions": [
  5.     {
  6.       "name": "John",
  7.       "age": 12
  8.     },
  9.     {
  10.       "name": "Jack",
  11.       "age": 32
  12.     }
  13.   ]
  14. }

我需要捕获/存储列表的名称，如 "friends"、"mates"、"companions"，因为我以后需要显示它们。我将有 20 个类似的 JSON 文件，唯一不同的是这个属性的名称。所以我需要从 JSON 中读取它并以某种方式存储它。

我想要一个更 "通用" 的类。这是否可行？如果您有其他建议，请告诉我。将不胜感激。

英文:

I want to convert JSON to object. The code below works fine.

  1. internal class Program
  2. {
  3.     static void Main(string[] args)
  4.     {
  5.         string json = @&quot;{
  6.                   &#39;name&#39;: &#39;Ayrton Senna&#39;,
  7.                   &#39;friends&#39;: [
  8.                     {
  9.                       &#39;name&#39;: &#39;John&#39;,
  10.                       &#39;age&#39;: 34
  11.                     },
  12.                     {
  13.                       &#39;name&#39;: &#39;Jack&#39;,
  14.                       &#39;age&#39;: 32
  15.                     }
  16.                   ]
  17.                 }&quot;;
  19.         var person = JsonConvert.DeserializeObject&lt;Person&gt;(json);
  20.     }
  22.     public class Person
  23.     {
  24.         public string Name { get; set; }
  25.         public List&lt;Friend&gt; Friends { get; set; }
  27.         public class Friend
  28.         {
  29.             public string Name { get; set; }
  30.             public int Age { get; set; }
  31.         }
  32.     }
  33. }

However in the Person Class I want the property List<Friend> to be dictionary.
The key will be string that should be "friends" (somehow taken from the Json and not hardcoded).
The value will be list of objects.

Example:

  1.     public class Person
  2.     {
  3.         public string Name { get; set; }
  4.         public Dictionary&lt;string, List&lt;Friend&gt;&gt; Friends { get; set; }
  6.         public class Friend
  7.         {
  8.             public string Name { get; set; }
  9.             public int Age { get; set; }
  10.         }
  11.     }

The reason I want this is so when i will have different JSON for example:

  1. {
  2.   &quot;id&quot;: 1,
  3.   &quot;name&quot;: &quot;Ayrton Senna&quot;,
  4.   &quot;mates&quot;: [
  5.     {
  6.       &quot;name&quot;: &quot;John&quot;,
  7.       &quot;age&quot;: 12
  8.     },
  9.     {
  10.       &quot;name&quot;: &quot;Jack&quot;,
  11.       &quot;age&quot;: 32
  12.     }
  13.   ]
  14. }

Another example Json:

  1. {
  2.   &quot;id&quot;: 1,
  3.   &quot;name&quot;: &quot;Ayrton Senna&quot;,
  4.   &quot;companions&quot;: [
  5.     {
  6.       &quot;name&quot;: &quot;John&quot;,
  7.       &quot;age&quot;: 12
  8.     },
  9.     {
  10.       &quot;name&quot;: &quot;Jack&quot;,
  11.       &quot;age&quot;: 32
  12.     }
  13.   ]
  14. }

I need to capture/store the name of the list like: "friends", "mates", "companions" because i will need to display them later. I will have 20 Json files like this and only this property name will be different. So i need to read ir from the json and store it somehow.

I want a class that will be more "generic".

Is this even doable? If you have some other suggestions please do tell. Any help will be much appreciated!

答案1

得分: 1

如果唯一的区别是数组的名称，您可以继续使用您已经有的类，并使用以下代码：

  1. var jObj = JObject.Parse(json);
  2. var friends =  jObj.Properties()
  3.                   .Where(p => p.Value.Type == JTokenType.Array)
  4.                   .SingleOrDefault();
  6. Person person = jObj.ToObject<Person>();
  7. person.FriendsKind = friends.Name;
  8. person.Friends = friends.Value.Select(p => p.ToObject<Friend>()).ToList();

公共类 Person 如下：

  1. public class Person
  2. {
  3.     public int Id { get; set; }
  4.     public string Name { get; set; }
  5.     public string FriendsKind { get; set; }
  6.     public List<Friend> Friends { get; set; }
  7. }
英文:

if the only difference is the array name, you can leave the class you have already and use this code

  1. 	var jObj = JObject.Parse(json);
  2.     var friends =  jObj.Properties()
  3.                       .Where(p =&gt; p.Value.Type == JTokenType.Array)
  4.                       .SingleOrDefault();
  5. 					
  6. 	Person person = jObj.ToObject&lt;Person&gt;();
  7.     person.FriendsKind= friends.Name;
  8. 	person.Friends = friends.Value.Select(p =&gt; p.ToObject&lt;Friend&gt;()).ToList();
  10. public class Person
  11. {
  12. 	public int Id { get; set; }
  13. 	public string Name { get; set; }
  14. 	public string FriendsKind {get; set;}
  15. 	public List&lt;Friend&gt; Friends { get; set; }
  16. }

答案2

得分: 1

以下是您要翻译的代码部分：

  1. var jObj = JObject.Parse(json);
  2. var friends = jObj.Properties().ToArray()[1];
  4. var person = new Person
  5. {
  6.     Name = jObj.GetValue("name").Value<string>(),
  7.     Friends = new Dictionary<string, List<Person.Friend>>
  8.     {
  9.         {
  10.             friends.Name,
  11.             friends.Value.Select(p => p.ToObject<Person.Friend>()).ToList()
  12.         }
  13.     }
  14. };
  16. public class Person
  17. {
  18.     public string Name { get; set; }
  19.     public Dictionary<string, List<Friend>> Friends { get; set; }
  21.     public class Friend
  22.     {
  23.         public string Name { get; set; }
  24.         public int Age { get; set; }
  25.     }
  26. }
英文: 
  1.     var jObj = JObject.Parse(json);
  2.     var friends = jObj.Properties().ToArray()[1];
  3.     
  4.     var person = new Person
  5.     {
  6.         Name = jObj.GetValue(&quot;name&quot;).Value&lt;string&gt;(),
  7.         Friends = new Dictionary&lt;string, List&lt;Person.Friend&gt;&gt;
  8.         {
  9.             {
  10.                 friends.Name,
  11.                 friends.Value.Select(p =&gt; p.ToObject&lt;Person.Friend&gt;()).ToList()
  12.             }
  13.         }
  14.     };
  16.     public class Person
  17.     {
  18.         public string Name { get; set; }
  19.         public Dictionary&lt;string, List&lt;Friend&gt;&gt; Friends { get; set; }
  21.         public class Friend
  22.         {
  23.             public string Name { get; set; }
  24.             public int Age { get; set; }
  25.         }
  26.     }

huangapple
  • 本文由 发表于 2023年2月14日 04:22:19
  • 转载请务必保留本文链接：https://go.coder-hub.com/75440809.html
  • c#
  • json.net
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