英文:
script to get source code of website (js)
问题
我的学校封锁了CTRL + U,但你可以在链接之前使用'view-source:'来查看代码。这需要一些时间,所以我一直在尝试制作一个自动定向到源代码的脚本。但是,我一直遇到错误,因为它不是一个链接。
我已经尝试过以下方法:
var code = fetch(`view-source:https://${location.hostname}${location.pathname}`);
location.href = code;
和
var code = `view-source:https://${location.hostname}${location.pathname}`;
location.href = code;
在第一个方法中,我看到一个坏请求,而在第二个方法中,我看到一个带有"view-source:"后跟链接的空白页面。
英文:
My school blocked CTRL + U, but you can use 'view-source:' before a link to view the code. It takes awhile, so i've been trying to make a script to automatically direct to the source code. However, I keep getting errors because it is not a link
I have tried the following:
var code = fetch(`view-source:https://${location.hostname}${location.pathname}`);
location.href = (code);
and
var code = (`view-source:https://${location.hostname}${location.pathname}`);
location.href = (code);
In the first one, I see a bad request, and in the second, I a blank page with the words "view-source:" followed by the link
答案1
得分: 1
view-source:
不是一个你可以使用 fetch()
的真实协议。
然而,只需
var resp = await fetch('http://...');
var text = await resp.text();
document.body.textContent = text;
应该用该URL的文本内容替换当前文档的主体内容...
英文:
view-source:
isn't a real protocol you can fetch()
.
However, just
var resp = await fetch('http://...');
var text = await resp.text();
document.body.textContent = text;
should replace the current document's body with the text contents of that URL...
答案2
得分: 1
如果您尝试从前端获取源代码,您将遇到CORS问题。但您可以像下面的示例中那样使用一些代理:
fetch('https://api.codetabs.com/v1/proxy?quest=https://stackoverflow.com/questions/75440023/script-to-get-source-code-of-website-js#75440023').then((response) => response.text()).then((text) => console.log(text));
英文:
If you try from frontend to fetch the source code you will run to CORS Problems. But you can use some proxyies like in the example beloow:
<!-- begin snippet: js hide: false console: true babel: false -->
<!-- language: lang-js -->
fetch('https://api.codetabs.com/v1/proxy?quest=https://stackoverflow.com/questions/75440023/script-to-get-source-code-of-website-js#75440023').then((response) => response.text()).then((text) => console.log(text));
<!-- end snippet -->
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