英文:
How can I obtain the number of times that a hold block changes its state?
问题
我正在建模供应链流程。情况是，当等待块达到其最大容量时，我会阻止保持块，以停止零部件的流动，当一个零部件离开等待块时，我会解除保持的阻塞。我尝试计算以下内容：
- 在整个模拟期间，保持块处于阻塞状态的时间（time()）。
- 在模拟过程中，此保持块从解除阻塞状态变为阻塞状态的次数（count）。
我尝试使用事件来计算这些内容，但我得到的结果不正确。您能帮助我吗？谢谢！
英文:
I am modelling a supply chain process. The case is that when the wait block reaches its maximum capacity I block the hold block in order to stop the flow of components and when one component exits the wait block I unblock the hold . What I am trying to calculate is:
- How much time is the hold in the block state during the whole simulation ( time()).
- The number of times that this hold block changed its state from unblocked to block during the simulation (count)
I tried to calculate this using events but the results that I am obtaining are not correct.Could you give me a hand with this? Thanks!
答案1
得分: 1
创建两个 double 类型的变量，命名为 timeBlocked 和 blockStartTime（初始值为 0）。还创建一个名为 blockCount 的变量，类型为 int（初始值也为 0）。
在你的代码中，每次阻塞 hold block 时，添加以下行：
blockStartTime = time();
blockCount++;
每次解除阻塞时，添加以下行：
timeBlocked += time() - blockStartTime;
现在额外注意一下，我看到你有多个 hold block，所以我建议对每个 block 都执行上述操作（即为每个 block 重复创建我建议的变量）。如果你有大量的 hold block 并提供更多细节，我们可能能够为你提供更精简的解决方案，但我想上述方法应该足够适用于你的模型。
英文:
Create two variables of type double and call them timeBlocked and blockStartTime (initial value = 0). Also create a variable called blockCount. This one can be of type int (initial value = 0 too).
In your code, every time you block the hold block, add the following line:
blockStartTime = time();
blockStart++;
Every time you unblock it, add the following:
timeBlocked += time() - blockStartTime;
Now as an extra note, I can see you have more than one hold block, so I would recommend doing the above for each one (i.e. create the variables I suggested twice, once for each block). If you have a ton of hold blocks and you provide more details, we may be able to give you a leaner solution, but I guess the above should work well enough for your model.
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