英文:
Pandas DF: Create New Col by removing last word from of existing column
问题
这似乎是一个很简单的目标，但我可能想得太多，但我卡住了。关于我应该做什么的建议将不胜感激。
以下是正确的翻译部分：
- "This should be easy, but I'm stumped." -> "这应该很容易，但我陷入了困境。"
- "I have a df that includes a column of
PLACENAMES. Some of these have multiple word names:" -> "我有一个包含PLACENAMES列的数据框。其中一些具有多个单词的名称：" - "All I want to do is to create a new column in my df that has just the name, without the "county" word:" -> "我想做的只是在我的数据框中创建一个新列，只包含名称，不包括“county”这个词："
- "1. Works - splits the names into a list
['St.','Louis','County']" -> "1. 有效 - 将名称分割成一个列表['St.','Louis','County']" - "2. The list splice is ignored, resulting in the same list
['St.','Louis','County']rather than['St.','Louis']" -> "2. 忽略了列表切片，导致相同的列表['St.','Louis','County']，而不是['St.','Louis']" - "3. Raises a ValueError:
Length of values (2) does not match length of index (41414)" -> "3. 引发了一个ValueError错误：值的长度（2）与索引的长度（41414）不匹配" - "4. Raises a TypeError:
sequence item 0: expected str instance, list found" -> "4. 引发了一个TypeError错误：序列项 0：期望 str 实例，但找到了列表" - "This also raises a TypeError:
sequence item 0: expected str instance, list found" -> "这也引发了一个TypeError错误：序列项 0：期望 str 实例，但找到了列表"
希望这有助于您解决问题。
英文:
This should be easy, but I'm stumped.
I have a df that includes a column of PLACENAMES. Some of these have multiple word names:
Able CountyBaker CountyCharlie CountySt. Louis County
All I want to do is to create a new column in my df that has just the name, without the "county" word:
AbleBakerCharlieSt. Louis
I've tried a variety of things:
1. places['name_split'] = places['PLACENAME'].str.split()2. places['name_split'] = places['PLACENAME'].str.split()[:-1]3. places['name_split'] = places['PLACENAME'].str.rsplit(' ',1)[0]4. places = places.assign(name_split = lambda x: ' '.join(x['PLACENAME].str.split()[:-1]))
- Works - splits the names into a list
['St.','Louis','County'] - The list splice is ignored, resulting in the same list
['St.','Louis','County']rather than['St.','Louis'] - Raises a ValueError:
Length of values (2) does not match length of index (41414) - Raises a TypeError:
sequence item 0: expected str instance, list found
I've also defined a function and called it with .assign():
def processField(namelist):words = namelist[:-1]name = ' '.join(words)return nameplaces = places.assign(name_split = lambda x: processField(x['PLACENAME]))
This also raises a TypeError: sequence item 0: expected str instance, list found
This seems to be a very simple goal and I've probably overthought it, but I'm just stumped. Suggestions about what I should be doing would be deeply appreciated.
答案1
得分: 1
places['name_split'] = places['PLACENAME'].str.rpartition()[0]
英文:
Apply Series.str.rpartition function:
places['name_split'] = places['PLACENAME'].str.rpartition()[0]
答案2
得分: 1
使用 str.replace 来移除最后一个单词和前面的空格：
places['new'] = place['PLACENAME'].str.replace(r'\s*\w+$', '', regex=True)# 或者places['new'] = place['PLACENAME'].str.replace(r'\s*\S+$', '', regex=True)# 或者，只匹配 'County'places['new'] = place['PLACENAME'].str.replace(r'\s*County$', '', regex=True)
输出：
PLACENAME new0 Able County Able1 Baker County Baker2 Charlie County Charlie3 St. Louis County St. Louis
英文:
Use str.replace to remove the last word and the preceding spaces:
places['new'] = place['PLACENAME'].str.replace(r'\s*\w+$', '', regex=True)# orplaces['new'] = place['PLACENAME'].str.replace(r'\s*\S+$', '', regex=True)# or, only match 'County'places['new'] = place['PLACENAME'].str.replace(r'\s*County$', '', regex=True)
Output:
PLACENAME new0 Able County Able1 Baker County Baker2 Charlie County Charlie3 St. Louis County St. Louis
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