从BIGINT纪元时间戳插入Redshift时如何提取年、月或日

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英文:

How to extract year, month or day from BIGINT epoch timestamp when inserting in Redshift

问题

从一个BIGINT时间戳1543258003796在Redshift SQL环境中插入数据到表格时,我想提取一个日期格式,比如月份、年份或日期。

我有这样一个表格:

CREATE TABLE time_table (
    month_date    character varying(20),
    year_date     character varying(20)
);

现在,我想用来自另一个表格ts_table的数据填充表格time_table,后者有一个以BIGINT类型表示的时间戳列:

INSERT INTO time_table (month_date, year_date)
SELECT EXTRACT(month from ts.timestamp) as month_date,
       EXTRACT(year from ts.timestamp)  as year_date
FROM ts_table ts;

它会引发错误,因为ts.timestamp是一个BIGINT。我应该首先将BIGINT转换为其他类型吗?或者有其他函数可以执行此操作吗?我尝试了几种方法,但仍然无法找到解决方案。

英文:

I would like to extract a date format like month, year or day from a BIGINT timestamp 1543258003796 in the Redshift SQL environment when inserting data into a table.

I have a table like this:

CREATE TABLE time_table (
    month_date    character varying(20),
    year_date     character varying(20),
);

Now I want to populate the table time_table with data from another table ts_table that has a column with timestamp as BIGINT type:

INSERT INTO time_table (month_date, year_date)
SELECT EXTRACT(month from ts.timestamp) as month_date,
       EXTRACT(year from ts.timestamp)  as year_date
FROM ts_table ts;

It raises an error because ts.timestamp is a BIGINT. Should I first cast the BIGINT into something else? Or is there another function to perform this action? I tried several things but I am still not able to find a solution.

答案1

得分: 1

我假设这些BIGINT日期是纪元日期。所以你首先需要将其转换为时间戳 - 例如像这样:

select timestamp 'epoch' + t.timestamp * interval '1 second' AS timest
from ts_table t;

现在这不是你想要的,但它将其转换为时间戳数据类型并为你打开了可用的有用函数。

第二步是从中提取年份和月份。将它们组合在一起,你会得到:

WITH ts_conv as (
  select timestamp 'epoch' + t.timestamp * interval '1 second' AS timest
  from ts_table t
)
SELECT EXTRACT(month from ts.timest) as month_date,
       EXTRACT(year from ts.timest)  as year_date
FROM ts_conv ts;

当然,这可以嵌入到你的INSERT语句中。

英文:

I assume that these BIGINT dates are epoch dates. So you first need to convert this to a timestamp - for example like so:

select timestamp 'epoch' + t.timestamp * interval '1 second' AS timest
from ts_table t;

Now this isn't want you want but it gets you into a timestamp data type and opens up the useful functions available to you.

Step 2 is to EXTRACT the year and month from this. Putting these together you get:

WITH ts_conv as (
  select timestamp 'epoch' + t.timestamp * interval '1 second' AS 
  timest
  from ts_table t
)
SELECT EXTRACT(month from ts.timest) as month_date,
       EXTRACT(year from ts.timest)  as year_date
FROM ts_conv ts;

And this of course can be inside your INSERT statement.

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  • 本文由 发表于 2023年2月14日 00:11:12
  • 转载请务必保留本文链接:https://go.coder-hub.com/75438437.html
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